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Tamiku [17]
2 years ago
9

A hover craft also known as a air cushion vehicle glides on a cushion of air allowing it to travel with equal is land or water.

The first commercial hovercraft to cross the English channel the V. A-3 had a average speed of 26.7 M/S. Its momentum at the speed was 4.8×10^4 KGM/S. What was the mass of the V. A-3?
Physics
1 answer:
dimaraw [331]2 years ago
4 0

Answer: M = 1797.75 kg

Explanation:

given parameters are;

speed V = 26.7 M/S.

momentum P = 4.8×10^4 KGM/S.

What was the mass of the V. A-3?

Momentum P is the product of mass and velocity. That is, P = MV

Substitute V and P into the formula

4.8×10^4 = 26.7 × M

Make M the subject of formula

M = 4.8×10^4/ 26.7

M = 1797.75 kg

Therefore, the mass of the V. A-3 was 1797.75 kg

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Yuri [45]

Answer:

yes

Explanation:

6 0
2 years ago
A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a sc
marshall27 [118]

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

8 0
3 years ago
Mimas, a moon of Saturn, has an orbital radius of 1.62 × 108 m and an orbital period of about 23.21 h. Use Newton’s version of K
Drupady [299]

Answer:

3.60432\times 10^{26}\ kg

Explanation:

a = Orbital radius = 1.62\times 10^8\ m

T = Orbital period = 23.21 hours

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

From Kepler's third law we get

M=\frac{4\pi^2a^3}{GT^2}\\\Rightarrow M=\frac{4\pi^2\times (1.62\times 10^8)^3}{6.67\times 10^{-11}\times (23.21\times 3600)^2}\\\Rightarrow M=3.60432\times 10^{26}\ kg

From the given data the mass of Saturn is 3.60432\times 10^{26}\ kg

8 0
2 years ago
what would happen to the surface temperature on Earth if large amounts of carbon dioxide were removed from the atmosphere?
slava [35]

Answer:

If carbon emissions stopped, the oceans catch up with the atmosphere, the Earth's temperature would rise about another 1.1F (0.6C).

Explanation:

8 0
3 years ago
Okay, so I've been stuck on this for a couple days. I've looked online and whatnot for answers or some help and nothing. So I ca
Lina20 [59]
Here are the Brief summary of the evolution  :

- After earth formed, Volcanoes emtted gas and meteroite brought ice
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- Cyanobacteria increased the amount of O2
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hope this helps
4 0
3 years ago
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