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grin007 [14]
3 years ago
11

A hockey puck is set in motion across a frozen pond. If ice friction and air resistance are neglected, the forcerequired to keep

the puck sliding at constant velocity isA) the weight of the puck divided by the mass of the puck.B) the mass of the puck multiplied by 9.8 meters per second per second.~qual to the weight of the puck.'i.£l/ero newtons.E) none of these.
Physics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

Zero Newtons

Explanation:

Newton's second law of motion states that the net force applied to an object is equal to the product between the object's mass and its acceleration:

F=ma

In this case, we want the hockey puck to slide at constant velocity - constant velocity means zero acceleration:

a = 0

And so this means also that the net force is zero:

F = 0

However, the problem says that ice friction and air resistance are negligible - so there are no forces acting on the hockey puck. This means that the puck will continue its motion at constant velocity if we don't apply any other force on it.

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Answer:

What is C - when your front bumper is even with the front vehicles back bumper.

Explanation:

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8 0
2 years ago
The source of heat for a (an) _____ system is electricity.
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The source of heart for a (an) close system is electricity.
6 0
3 years ago
An observer sees a flower pot sail up and then back down past a window 2.45 m high. If the total time the pot is in the sight is
Fynjy0 [20]

Answer: 2.55meter

Explanation: Using the second equation of motion.

S{hieght} = U*t + {g*t²}/2

Where U is initial velocity =0m/s

g is acceleration due to gravity 10m/s²

t is time 1secs

So we have,

hieght = 0 + {g*t²}/2

hieght = {10*(1)²}/2

Total hieght travelled is 10/2

Which is 5 meter.

But we are asked to find the hieght above the window which as a hieght of 2.45meter.

So,

hieght above window would be

{5 - 2.45}meter

Which is 2.55 meter.

8 0
3 years ago
A rock is thrown straight down, not dropped, from the roof of a building that is 61 m above the ground. If it takes 3.1 s to rea
PtichkaEL [24]
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4 0
3 years ago
A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result
Over [174]
B) law of conservation of momentum

It states that the total momentum of a system before impact is the same as the total momentum of the system after impact.

In this case total momentum before impact:

10kg*5m/s  + 5kg * 0m/s = 50 kg m/s

After Impact:

10kg*0m/s + 5kg*10m/s = 50 kg m/s

You can see the momentum before and after impact is same as 50 kg m/s  

Of course we assumed that the first cart stopped after the impact, and there are no energy losses.
7 0
3 years ago
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