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grin007 [14]
3 years ago
11

A hockey puck is set in motion across a frozen pond. If ice friction and air resistance are neglected, the forcerequired to keep

the puck sliding at constant velocity isA) the weight of the puck divided by the mass of the puck.B) the mass of the puck multiplied by 9.8 meters per second per second.~qual to the weight of the puck.'i.£l/ero newtons.E) none of these.
Physics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

Zero Newtons

Explanation:

Newton's second law of motion states that the net force applied to an object is equal to the product between the object's mass and its acceleration:

F=ma

In this case, we want the hockey puck to slide at constant velocity - constant velocity means zero acceleration:

a = 0

And so this means also that the net force is zero:

F = 0

However, the problem says that ice friction and air resistance are negligible - so there are no forces acting on the hockey puck. This means that the puck will continue its motion at constant velocity if we don't apply any other force on it.

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With what tension must a rope with length 2.20 m and mass 0.150 kg be stretched for transverse waves of frequency 43.0 hz to hav
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Solution:

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What is the ionisation energy of an atom
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Explanation:

its the minimum amount of energy required to remove the most loosely bound electron

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An object has a kinetic energy of 275 j and a momentum of magnitude 25.0 kg · m/s. find the (a) speed and (b) mass of the object
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There are four springs stretched by the same mass.
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Spring C stretches 100 cm.

Explanation:

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Spring constant shows the force needed to stretch a spring from it's equilibrium position. If a material requires more force to cause it to stretch, it will have a high spring constant.

          According to hooke's law "the force needed to extended an elastic material is directly proportional to its extension"

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We see that the spring that stretches by 100 is the less stiff compared to other springs. It has the smallest spring constant.

Learn more;

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Future space stations could create an artificial gravity by rotating. Consider a cylindrical space station that rotates with a p
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Answer:

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So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2

Also, F / m = 9.8 m/s^2   earth's gravitational attraction

So 9.8 = 4 pi^2 R / P^2    or    R = 9.8 P^2 / 4 * pi^2) = 195 m

Or D = 2 R = 390 m the diameter required

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2 years ago
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