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Alina [70]
3 years ago
12

Newton's _____ law explains why my hands hurt when I clap loudly

Physics
2 answers:
kakasveta [241]3 years ago
4 0

Answer:

third :p

Explaination:

Basile [38]3 years ago
3 0
Newtons third law (inertia) is to blame
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Two similar gold spheres are separated by a distance of
solong [7]

Answer:

The answer to your question is the letter D. 2.5 N

Explanation:

The electrostatic force is the same in both directions,

If the electrostatic force on B due to A is 2.5 N, the magnitude of the electrostatic force on A due to B must be 2.5N.

Maybe the direction is different but the magnitude is the same.

5 0
3 years ago
A 2.0-kg object is attached to a spring (k = 55.6 N/m) that hangs vertically from the ceiling. The object is displaced 0.045 m v
rusak2 [61]

Answer:

Maximum acceleration will be 1.251m/sec^2

Explanation:

We have given mass of the object m = 2 kg

Spring constant k = 55.6 N/m

Amplitude is given as A = 0.045 m

We know that maximum acceleration in SHM is given by

Maximum acceleration =A\omega ^2

We know that \omega ^2=\frac{k}{m}=\frac{55.6}{2}=27.8

So maximum acceleration = 27.8\times 0.045=1.251m/sec^2

8 0
3 years ago
Read 2 more answers
Describe how Rutherford's experiments changed the accepted scientific model of the atom.
lorasvet [3.4K]

Rutherford's model of the atom (ESAAQ) Rutherford carried out some experiments which led to a change in ideas around the atom. His new model described the atom as a tiny, dense, positively charged core called a nucleus surrounded by lighter, negatively charged electrons.

4 0
3 years ago
Two particles with oppositely signed charges nC are placed at two of the vertices of an equilateral triangle with side length 3
babymother [125]

The magnitude of the electric field at the third vertex of the triangle is determined as zero.

<h3>Electric field at the third vertex of the triangle </h3>

The electric field at the third vertex of the equilateral triangle due to the other charges placed on the first and second vertices is calculated as follows;

E = E(13) + E(23)

E = (kq₁)/r² + (kq₂)/r²

where;

  • q1 is positive charge
  • q2 is negative charge

E =  (kq₁)/r² - (kq₂)/r²

E = 0

Thus, the magnitude of the electric field at the third vertex of the triangle is determined as zero.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

5 0
2 years ago
A physics student spends part of her day walking between classes or for recreation, during which time she expends energy at an a
kondor19780726 [428]
RESULT: Twalk= 3.64 hr

7 0
3 years ago
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