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3 years ago

find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons

Physics

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

0.02

Explanation:

Force, $F=\mu_k N$ where N is normal reaction and coefficient of kinetic friction is $\mu_k$ . Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making $\mu$ the subject of the formula then

$\mu_k=\frac {F}{mg}$

Substituting F with 2 N, m with 10 kg and g with 9.81 then

$\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02$

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galina1969 [7]

Answer:

0.04225 Nm

Explanation:

N = Force applied = 5 N

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$F=N\mu\\\Rightarrow F=5\times 0.65\\\Rightarrow F=3.25\ N$

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$\tau_t=F\times r\\\Rightarrow \tau_t=3.25\times 0.0065\\\Rightarrow \tau_t=0.021125\ Nm$

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$\tau_f=F\times r\\\Rightarrow \tau_f=3.25\times 0.0065\\\Rightarrow \tau_f=0.021125\ Nm$

The total torque is given by

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2 years ago

A firefighter of mass 81 kg slides down a vertical pole with an acceleration of 3 m/s 2 . The acceleration of gravity is 10 m/s

natima [27]

Answer:

The force of friction that acts on him is

$F_k=567N$

Explanation:

The firefighter with an acceleration of 3m/s^2 take the gravity acceleration as 10m/s^2 isn't necessary to know the coefficient of friction just to know the force of friction:

$F=m*a$