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insens350 [35]
3 years ago
5

find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​

Physics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

0.02

Explanation:

Force, F=\mu_k N where N is normal reaction and coefficient of kinetic friction is \mu_k. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making \muthe subject of the formula then

\mu_k=\frac {F}{mg}

Substituting F with 2 N, m with 10 kg and g with 9.81 then

\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02

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