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3 years ago

15

Which type of magma is known for the most violent eruptions?

2 answers:

Anni [7]3 years ago

8 0

Answer: B. Rhyolitic

Rhyolitic magma is responsible for most violent volcanic eruptions. Rhyolitic magma erupts catastrophically with high intensity gas content. This magma being more viscous traps gases, builds pressures and erupts explosively. High viscosity of this magma is because of high silica content that erupt with the mineral contents of the rocks.

lukranit [14]3 years ago

5 0

Answer:

its............................................................BBBBB

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How do I convert 498.82 cg to mg

mezya [45]

<span><u><em>Answer:</em></u>
498.82 cg is equivalent to 4988.2 mg

<u><em>Explanation:</em></u>
cg stands form centigrams
mg stands for milligrams

From the standards of conversion, to convert from centi to milli, we multiply the amount ny 10

<u>This means that:</u>
1 centigram = 10 milligram

To convert 498.82 cg to mg, all we have to do is <u>cross multiplication</u> as follows:
1 cg ..................> 10 mg
498.82 cg .........> ?? mg

498.82 cg = </span> $\frac{498.82*10}{1}$ <span> = 4988.2 mg

Hope this helps :)</span>

3 0

3 years ago

Read 2 more answers

An optical disk drive in a computer can spin a disk at up to 10,000 rpm. If a particular disk is spun at 7570 rpm while it is be

anastassius [24]

Answer:

The magnitude of the average angular acceleration is calculated as $1822.36\ rad/s^{2}$

Explanation:

Maximum speed that can be attained by the disk, $N_{m}$ = 10,000 rpm

Speed of spinning of the disk, N = 7570 rpm

Time taken to come to rest, t = 0.435 s

Now,

The initial angular velocity is given by:

$\omega = \frac{2\pi N}{60} = 792.73\ rads^{-1}$

Final angular velocity, $\omega' = 0\ rads^{- 1}$

The average angular acceleration of the disk can be computed by using the kinematic eqn:

$\omega' = \omega + \alpha t$

$0 = 792.73 + 0.435\alpha$

$\alpha = - 1822.36\ rads^{- 2}$

5 0

3 years ago

Read 2 more answers

The distance between the centers of the wheels of a motorcycle is 156 cm. The center of mass of the motorcycle, including the ri

Drupady [299]

Answer:

a = 9.86 m/s²

Explanation:

given,

distance between the centers of wheel = 156 cm

center of mass of motorcycle including rider = 77.5 cm

horizontal acceleration of motor cycle = ?

now,

The moment created by the wheels must equal the moment created by gravity.

take moment about wheel as it touches the ground, here we will take horizontal distance between them.

then, take the moment around the center of mass. Since the force on the ground from the wheels is horizontal, we need the vertical distance.

now equating both the moment

m g d = F h

d is the horizontal distance

h is the vertical distance

m g d = m a h

term of mass get eliminated

g d = a h

so,

$a = \dfrac{g\ d}{h}$

$a = \dfrac{9.8\times 0.78}{0.775}$

a = 9.86 m/s²

4 0

3 years ago

A student walks 4 blocks east, 7 blocks west, 1 block east and then 2 blocks west in an hour what is their velocity

Nutka1998 [239]

Answer:

4 blocks west is final displacement. So 4 blocks per hour

3 0

2 years ago

Which bike rider has the greatest momentum?

Sphinxa [80]

My guesses would be g. or F

5 0

3 years ago