Answer:
(4 + 7i)(4 – 7i)
Step-by-step explanation:
This pair will produce a real answer because they are complex conjugates.
Complex conjugates ( a+bi) (a-bi) when multiplied together form a real number ( a^2 + b^2)
Answer:
part a: she borrowed 3,700
part b: she would pay 555 interest
Step-by-step explanation:
Answer:
a) OA = 1 unit
b) OB = 3 units
c) AB = √10 units
Step-by-step explanation:
<u>Given function</u>:

<h3><u>Part (a)</u></h3>
Point A is the y-intercept of the exponential curve (so when x = 0).
To find the y-value of Point A, substitute x = 0 into the function:

Therefore, A (0, 1) so OA = 1 unit.
<h3><u>Part (b)</u></h3>
If BC = 8 units then the y-value of Point C is 8.
The find the x-value of Point C, set the function to 8 and solve for x:

Therefore, C (3, 8) so Point B is (3, 0). Therefore, OB = 3 units.
<h3><u>Part (c)</u></h3>
From parts (a) and (b):
To find the length of AB, use the distance between two points formula:


Therefore:





Answer:
y^2 - 10y + 25
Step-by-step explanation:
(y - 5)^2 =
(y - 5) • (y - 5)
Multiply y times y
y^2
Add 5 and 5
10
Multiply 5 and 5
25
Add these terms together
y^2 - 10y + 25