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Nata [24]
3 years ago
15

What is 674×673×142÷3​

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

Step-by-step explanation:

674 \times 673 \times 142 \div 3 \\  \\ =  674 \times 673 \times 142  \times  \frac{1}{3}  \\  \\  = 64,411,484\times  \frac{1}{3}   \\  \\  = 21,470,494.7 \\

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The equation P=6s represents the perimeter P of a regular hexagon with side length s. What is the perimeter of a regular hexagon
Verdich [7]

we know that s = 3, so plug it in.

P = 6(3)

P = 18

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2 years ago
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The triangles below are similar.<br> Pls help me
siniylev [52]

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Step-by-step explanation: The left triangle has the angles 5 and 4, so the right answer for the other side would be the angles 8 and x=9.

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Find the least common multiple.
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Answer:

C - 3,600

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3 years ago
In the historical account of Rome, another name for the Romans is the
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(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this
Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta

Simplify. The denominator uses the difference of two squares pattern:

\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta

Split into two separate fractions:

\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta

Rewrite the two fractions:

\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=}  \sec^2\theta - \sec\theta\tan\theta

Hence verified.

8 0
2 years ago
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