Answer:
C
Step-by-step explanation:
We can solve simultaneous equations using substitution method, elimination method or graphical method. But for this purpose, we will be using the elimination method.
3x+4y=8 Equation 1
2x+y=42 Equation 2
Multiply Equation 1 by 2 and equation 2 by 3, so as to get the same coefficient for x
2(3x+4y=8)= 6x+8y=16 Equation 3
3(2x+y=42)= 6x+3y=126 Equation 4
Subtract equation 4 from 3, to eliminate x
6x-6x=0
8y-3y= 5y
16-126= -110
We now have 5y=-110
Divide both sides by 5,
y= -110/5
= -22
Substituting for y in equation 2
2x+(-22)= 42
2x= 42+22
2x=64
x= 64/2
= 32
(x, y)
(32, -22)
So it is asking you to group like term so
x terms can be grouped/added/subtracted to other x terms, but not to x^2 or x^3 terms
x^2 terms to x^2 and so on so
1. 9-3k+5k=
9+(5k-3k)=
9+2k
2. k^2+2k+4k=
k^2+(2k+4k)=
k^2+6k=
X= -2 because I love school soooo much
To solve this, I would just find what two adult tickets and one child ticket wold be worth.
To find that, just do:
5.20 + 9.90 * 2, which makes 25.
So now you just find how many 25s are in 900, or 36.
So 36 children's tickets were sold that day.
Hope I helped :)
9514 1404 393
Answer:
$6307.95
Step-by-step explanation:
The compound interest formula can help with that.
A = P(1 +r/n)^(nt) . . . . value of principal P at rate r for t years, compounded n times per year.
P = A(1 +r/n)^(-nt) = $8000(1 +0.04/2)^(-2·6) = $8000(1.02^-12) = $6307.95
Momba needs to deposit $6307.95 today to have $8000 in 6 years.
