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3 years ago

Car A went 60 km in 5 6 hour while a car B went 54 km in 2 3 hour. Which car was faster? How many times faster?

Mathematics

1 answer:

Alexxx [7]3 years ago

4 0

Answer:car B is faster

Step-by-step explanation:

Car A:

Speed=distance ➗ time

Speed=60 ➗ 5/6

Speed=60 x 6/5

Speed=(60x6)/5

Speed=360/5

Speed of car A=72 km/hr

Car B:

Speed=distance ➗ time

Speed=54 ➗ 2/3

Speed=54 x 3/2

Speed=(54x3)/2

Speed=162/2

Speed of car B=81 km/hr

Therefore car B is faster

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Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

$v_1 = 60\ mph$

Sheyna drives back from the lake with average speed of 36 mph

$v_2 = 36\ mph$

It took 2 hours less time to get there than it did to get back.

Let $t_1$ be the time taken to drive to lake.

Let $t_2$ be the time taken to drive back from lake.

$t_2-t_1 = 2$ hrs ..... (1)

To find:

Total time taken = ?

$t_1+t_2 = ?$

Solution:

Let D be the distance to lake.

Formula for time is given as:

$Time =\dfrac{Distance}{Speed }$

$t_1 = \dfrac{D}{60}\ hrs$

$t_2 = \dfrac{D}{36}\ hrs$

Putting in equation (1):

$\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles$

So,

$t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs$

$t_2 = \dfrac{180}{36}\ hrs = 5\ hrs$

So, the answer is:

$t_1+t_2 = \bold{8\ hrs}$

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