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ahrayia [7]
4 years ago
8

Potassium chlorate decomposes according to the following chemical equation:

Chemistry
2 answers:
kari74 [83]4 years ago
5 0

Answer:

179.4 g of oyxgen will be produced.

Option 2.

Be careful because the units says L instead of g

Explanation:

Decomposition reaction:

2KClO₃ → 2KCl + 3O₂

2 moles of chlorate can decompose to 2 moles of chloride and 3 moles of oxygen.

We convert the mass to moles, and then we make the rule of three:

458 g / 122.55 g/mol =3.74 moles of chlorate

2 moles of chlorate can produce 3 moles of oxygen

Then, 3.74 moles of chlorate may produce (3.74 .3) / 2 = 5.60 moles of O₂

We convert the moles to mass → 5.60 mol . 32 g / 1mol = 179.4 g

Sedaia [141]4 years ago
5 0

Answer:

179.39 grams of O2 will be produced (option 2 is correct)

Explanation:

Step 1: Data given

Mass of KClO3 = 458 grams

Molar mass KClO3 = 122.55 g/mol

Molar mass O2 = 32.0 g/mol

Step 2: The balanced equation

2KCIO3 → 2KCI + 3O2

Step 3: Calculate moles KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3 = 458 grams / 122.55 g/mol

Moles KClO3 = 3.74 moles

Step 4: Calculate moles of O2

For 2 moles KClO3 we'll have 2 moles KCl and 3 moles O2

For 3.74 moles we'll have 3/2 * 3.74 = 5.606 moles

Step 5: Calculate mass O2

Mass O2 = 5.606 moles * 32.0 g/mol

Mass O2 = 179.39 grams

179.39 grams of O2 will be produced (option 2 is correct)

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How many grams of a 5.5% solution can be prepared from 25 kg KCl
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Answer:

The percentage concentration of any solution is most commonly expressed as mass percent:

Mass % of any component of the solution =

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Other methods are:

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Mass by volume percentage:

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i.e. Mass by Volume percentage =

(Mass of solute in grams/Volume of solution in mL) x 100

Here's a point to be kept in mind :

Whenever we say mass or volume of the solution, you need to add the respective masses and volumes of ALL the components of the solution. Do NOT commit the error of taking the mass or volume of only the solute or solvent in the denominators of the above expressions.

The concentration of a solution is most of the time expressed as the number of moles of solute present in 1 Liter of the solution (also called molarity )

(There are also other ways to express concentration. Please follow this link. )

EXAMPLE:

(a) If 25 moles of NaCl are present in 100 L of a solution wherein H2O is the solvent, then the concentration of the solution is

25

100

=

0.25

mol⋅L

−

1

.

(b) What is the molarity of a solution prepared by dissolving 15.0 g of sodium hydroxide in enough water to make a total of 225 mL of solution?

Solution

Calculate the number of moles of solute present.

Moles of NaOH = 15.0 g NaOH ×

1

mol NaOH

40.00

g NaOH

= 0.375 mol NaOH

Calculate the number of litres of solution present.

Volume = 225 mL ×

1

L

1000

mL

= 0.225 L soln

Divide the number of moles of solute by the number of litres of solution.

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0.375

mol

0.225

L

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Explanation:

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