Answer:
179.39 grams of O2 will be produced (option 2 is correct)
Explanation:
Step 1: Data given
Mass of KClO3 = 458 grams
Molar mass KClO3 = 122.55 g/mol
Molar mass O2 = 32.0 g/mol
Step 2: The balanced equation
2KCIO3 → 2KCI + 3O2
Step 3: Calculate moles KClO3
Moles KClO3 = mass KClO3 / molar mass KClO3
Moles KClO3 = 458 grams / 122.55 g/mol
Moles KClO3 = 3.74 moles
Step 4: Calculate moles of O2
For 2 moles KClO3 we'll have 2 moles KCl and 3 moles O2
For 3.74 moles we'll have 3/2 * 3.74 = 5.606 moles
Step 5: Calculate mass O2
Mass O2 = 5.606 moles * 32.0 g/mol
Mass O2 = 179.39 grams
179.39 grams of O2 will be produced (option 2 is correct)