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marissa [1.9K]
3 years ago
7

Please help!!!! Look at the picture for the question.

Chemistry
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

C

Explanation:

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Can someone please help me quickly!!!
galina1969 [7]

Answer:

Mercury

Explanation: Under standard conditions mercury is a shiny, heavy, silvery liquid. It is the only metal that is liquid at room temperature.

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3 years ago
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What percent of all the genes in E. coli are active all the time
Alisiya [41]
60% are active all the time.
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3 years ago
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I'm redoing the Heat of Combustion Lab for a better grade and I REALLY need the answers and work for all questions! PLEASE!
I am Lyosha [343]

Answer:

Hi, what are the problems on the lab?

Explanation:

5 0
3 years ago
2H+ H- H+ n + energy
lbvjy [14]

from an external source of power

Explanation:

The energy needed for nuclear fusion comes from an external source of power.

Nuclear fusion is the combination of small sized atomic nuclei to form larger ones.

The reaction releases a huge amount of energy but also requires a large activation energy to start up.

  • The energy input require to drive two nuclei into fusion comes from an external source.
  • Nuclear fusion has a high activation energy which serves as the energy barrier for this reaction to take place.
  • The energy comes from the surrounding and once initiated, spontaneous chain reactions are set up.

learn more:

Nuclear reactions brainly.com/question/10094982

#learnwithBrainly

5 0
3 years ago
A certain substance X has a normal freezing point of 5.6 °C and a molal freezing point depression constant Kf-7.78 °C-kg·mol-1.
Harrizon [31]

Answer:

27.60 g urea

Explanation:

The <em>freezing-point depression</em> is expressed by the formula:

  • ΔT= Kf * m

In this case,

  • ΔT = 5.6 - (-0.9) = 6.5 °C
  • Kf = 7.78 °C kg·mol⁻¹

m is the molality of the urea solution in X (mol urea/kg of X)

First we<u> calculate the molality</u>:

  • 6.5 °C = 7.78 °C kg·mol⁻¹ * m
  • m = 0.84 m

Now we<u> calculate the moles of ure</u>a that were dissolved:

550 g X ⇒ 550 / 1000 = 0.550 kg X

  • 0.84 m = mol Urea / 0.550 kg X
  • mol Urea = 0.46 mol

Finally we <u>calculate the mass of urea</u>, using its molecular weight:

  • 0.46 mol * 60.06 g/mol = 27.60 g urea

7 0
3 years ago
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