The solution would be like
this for this specific problem:
<span>25.0 g CCl4 x (1 mole CCl4
/ 153.8 g CCl4) = 0.163 moles CCl4
</span>(29.82 kJ / mole)(0.163 moles) = 4.86 kJ
total heat = 1.11 kJ + 4.86 kJ = 5.97 kJ
<span>I hope this helps and if you have
any further questions, please don’t hesitate to ask again. </span>
A). Object A, because the shorter the distance between objects result in a stronger gravitational force
Elements cannot be broken down in this fashion.
Compounds, homogeneous mixtures, and heterogeneous mixtures can be broken down or separated with chemical processes, or in some cases, just by manual separation.
Answer:
falling water that turns turbines
Explanation:
Answer:
a. 300 kg of Fertilizer
b. 225 kg of fertilizer
c.400 Kg of fertilizer
d.600 Kg of fertilizer
Explanation:
The percentage composition ratio of Nitrogen, Phosphorus and Potassium bag of the given fertilizer is 40:15:10.
The percentages can be expressed as fractions as follows:
For nitrogen; 40/100 = 0.4
For phosphorus; 15/100 = 0.15
For potassium; 10/100 = 0.1
To find the quantity of fertilizer required to add to a hectare to supply the given amount of nutrients, the amount to be provided is divided by the percentage or fractional compostion of each nutrient.
Quantity of fertilizer required to add to a hectare to supply;
a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer
b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer
c. Phosphorus at 60 kg/ha = 60/0.15 = 400 Kg of fertilizer
d. Potassium at 60 kg/ha = 60/0.1 = 600 Kg of fertilizer
