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german
4 years ago
6

The empirical formula for a compound is ch2o, and the molar mass is 180.2 g/mol. which is the molecular formula for this compoun

d?
Chemistry
1 answer:
alekssr [168]4 years ago
3 0
<span>C6H12O6

Good luck. =]</span>
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What is the pressure in a 5.00 L tank with<br> 7.10 moles of oxygen at 39.3 °C?
Katena32 [7]

Answer:

36.4 atm

Explanation:

To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = ? atm                         R = 0.0821 L*atm/mol*K

V = 5.00 L                       T = 393 °C + 273.15 = 312.45 K

n = 7.10 moles

PV = nRT

P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)

P(5.00 L) = 182.130

P = 36.4 atm

8 0
2 years ago
Can someone do these? Brainliest included
mixas84 [53]

Answer:

Explanation:

6.         p⁺      e⁻

Ca²⁺    20     18

F⁻          9      10

O²⁻        8      10

Na⁺       11      10

7. Physical properties of matter are properties that can be measured or observed without matter changing to an entirely different substance. These include odor, boiling point, melting point, density, electrical conductivity and heat conductivity.

Separation of mixture:

Chromatography involves solvent separation on a solid medium.

Distillation takes advantage of differences in boiling points.

Evaporation removes a liquid from a solution to leave a solid material.

Filtration separates solids of different sizes.

Funnel partitioning with solvents. Solvent dissolves one component but not the other.

8.Bulk Elements => Carbon, Hydrogen, Oxygen, Nitrogen, Sulfur & Phosphouous

Microminerals are those minerals needed in less than 100 mg quantities. Trace minerals or trace elements are usually needed in microgram quantities. Microminerals include iron, zinc, copper, iodine, fluoride, chromium, cobalt, selenium, manganese, and molybdenum.

Diatomic Molecules => H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂

9. Electron Configurations

    Na: 1s²2s²2p⁶3s¹ => valence = 3s¹

    N:   1s²2s²2p³ => valence = 2s²2p³

    Al:  1s²2s²2p⁶3s²3p¹ => valence = 3s²3p¹

Valence is the highest principle quantum number (or, principle energy level  ~ ring) in the electron configurations.

10.moles of glucose = 450g/180.16 g/mol =2.50 moles

   C₂H₆O₂ = 2(12) + 6(1) + 2(16) = 24 + 6 + 32 = 62 g/mole

7 0
3 years ago
What can be used to determine the absolute age of two rocks? *
Aneli [31]

Answer:Ithink erosion cuz if we can tell how long ago it eroded we can see how old it is

Explanation:

6 0
3 years ago
Vinegar 59g, Oil 177g, Brown sugar 10g, and total mass
denis-greek [22]

Answer:

Total mass = 246 g

Explanation:

Given data:

Mass of vinegar = 59 g

Mass of oil = 177 g

Mass of brown sugar = 10 g

Total mass = ?

Solution:

Total mass = masses of [sugar + oil + vinegar]

Total mass = 59 g + 177 g + 10 g

Total mass = 246 g

3 0
3 years ago
The Lyman series results from excited state hydrogen atoms transiting to
Nutka1998 [239]

Answer:

I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.

n = 5 4th excited state

n = 4 3rd excited state

n = 3 2nd excited state

n = 2 1st excited state

n = 1 ground state

Here are the possible spectral lines.

n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.

n = 4 to 3, 4 to 2, 4 to 1 = 3 lines

n = 3 to 2, 3 to 1 = 2 lines

n = 2 to 1 = 1 line. Add 'em up. I get 10.

b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.

c.The E for any level is -21.8E-19 Joules/n^2

To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.

So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.

Explanation:

8 0
3 years ago
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