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levacccp [35]
3 years ago
13

A man weighing 48 newtons climbs a 2.0-meter ladder. How much work is done? 0.0 J 24 J 96 J 124 J

Chemistry
2 answers:
Hoochie [10]3 years ago
5 0

Answer:C) 96 j

explanation:48 N * 2.0 m = 96. Your answer should be C, 96 joules.

oee [108]3 years ago
5 0

<u>Answer:</u> Work done by the man will be 96 J.

<u>Explanation:</u>

Work is defined as the amount of energy that is transferred in order to move an object by an external force. It is expressed in joules.

Mathematically,

W=F\times d

Where,

W = Work done = ? J

F = Force applied = 48 N

d = Displacement of the body = 2 m

Putting values in above equation, we get:

W=48\times 2=96J

Hence, work done by the man will be 96 J.

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3 years ago
Find the density if the volume is 15 mL and the mass is 8.6 g. (5 pts)
allsm [11]

Answer:

\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}

Explanation:

1. Density from mass and volume

\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}

2. Volume from density and mass

V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}

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4. Density by displacement

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Volume of water                =<u> 12.8 mL</u>

Volume of object               = 11.8 mL

\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}

Your drawing showing water displacement using a graduated cylinder should resemble the figure below.

 

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Hopefully that makes sense and i did the math right.... 
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