(2,-4) and (6,2). Find the mid point
2 answers:
Answer:
The answer is
<h2>( 4 , - 1)</h2>Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(2,-4) and (6,2)
The midpoint is
We have the final answer as
<h3>( 4 , - 1)</h3>Hope this helps you
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Answer:
(2,-1)
Step-by-step explanation:
A graph is useful here. Points X and Y have coordinate differences of ...
X -Y = (6, 2) -(-2, -4) = (6+2, 2+4) = (8, 6)
Then the distance between X and Y is ...
d = √(8² +6²) = √100 = 10
The point 5 units from X and from Y is the midpoint of XY:
E = (X +Y)/2 = ((6, 2) +(-2, -4))/2 = (4, -2)/2 = (2, -1)
The epicenter is (2, -1).
_____
The graph shows circles of radius 5 around X and Y, and a circle of radius 13 around Z. The circles intersect at the point (2, -1), the epicenter.
First multiply 3 and the 1
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve