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3 years ago

4/9 444/1000 0.4 least to greatest

Mathematics

1 answer:

vichka [17]3 years ago

8 0

4/9 0.4 444/1000 is the answer to the problem

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Please help. I don't understand

Andreas93 [3]

Answer:

Length of third side is: $\mathbf{8m^3-4m^2+3m}$

Step-by-step explanation:

Perimeter of triangle = $18m^3+2m^2-m$

Length of side 1= $5m^3+3m^2-2m$

Length of side 2= $5m^3+3m^2-2m$

We need to find length of third side.

The formula used is: $Perimeter \:of\:triangle=Sum\:of\:all\:sides$

Putting values and finding length of third side.

$Perimeter \:of\:triangle=Sum\:of\:all\:sides\\18m^3+2m^2-m=5m^3+3m^2-2m+5m^3+3m^2-2m+Length\:of\:3rd\:side\\18m^3+2m^2-m=5m^3+5m^3+3m^2+3m^2-2m-2m+Length\:of\:3rd\:side\\18m^3+2m^2-m=10m^3+6m^2-4m+Length\:of\:3rd\:side\\Length\:of\:3rd\:side=18m^3+2m^2-m-(10m^3+6m^2-4m)\\Length\:of\:3rd\:side=18m^3+2m^2-m-10m^3-6m^2+4m\\Length\:of\:3rd\:side=18m^3-10m^3+2m^2-6m^2-m+4m\\Length\:of\:3rd\:side=8m^3-4m^2+3m$

So, Length of third side is: $\mathbf{8m^3-4m^2+3m}$

5 0

3 years ago

Find the prime factorization for 100.

OleMash [197]

Answer:

100

Step-by-step explanation:

So, the prime factors of 100 are written as 2 x 2 × 5 x 5 or 25*4

8 0

2 years ago

In an auditorium, 1/6 of the students are 5th Graders, 1/3 are 4th Graders, and 1/4 of the remaining students are 2nd graders. I

avanturin [10]

1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12

5 0

3 years ago

If s(x) = x-7 and f(x) = 4x? – X+3, which expression is equivalent to (tos)(x)?

lesya692 [45]

Answer:

4(x-7)^2-(x-7)+3 (Assuming t is f)

Step-by-step explanation:

Let s(x)=x-7 and t(x)=4x^2-x+3 .

(t o s)(x)=t(s(x))=t(x-7)

Before I continue this means replace the orginal x in t with x-7.

This will then give you

4(x-7)^2-(x-7)+3

4 0

3 years ago

Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

5 0

2 years ago

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