Answer:
Variance is
Solution:
As per the question:
Average value of the steam, = 25000 pounds per hour,
To calculate the variance, of the steam:
where
= standard deviation
at 0.8 is 1.285 from Z-table
Thus
Variance,
Answer:
Q= 12 KJ
Heat enters to the system.
Explanation:
Given that
m= 5 kg
P₁ = 400 KPa
T₁ = 30⁰C = 303 K
Work done by the system ,W₁= 15 KJ
Work is done on the system W₂ = - 3 KJ'
Given that expansion is isothermal ,that is why temperature of the gas will remain constant.We know that internal energy of the ideal gas only depends on the temperature of the gas.That is why change in the internal energy of the gas will be zero because change in the temperature is zero.
From first law of thermodynamics
Q = W + ΔU
Q= =Heat ,W= Net Work ,ΔU =Change in the internal energy
Here ΔU = 0
Q= W
Q= 15 - 3 KJ
Q= 12 KJ
Heat enters to the system.
Note -
Work done on the system will be taken as negative and work done by the system taken as positive.
Heat added to the system will be taken as positive heat leaving from the system taken as negative.
' B ' is the only true one.
Emit radiation exactly equal in energy, to the energy difference between states.
Answer:
Frequency will be 4.30 kHz
Explanation:
We have inductance
And capacitance
Inductive reactance is given by
And capacitive reactance
As in question it is given that inductive reactance and capacitive reactance is same
So
We know that angular frequency
f = 4303.66 Hz =4.30 kHz