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Eduardwww [97]
3 years ago
15

Click through to find the correct identity.

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

b.

Step-by-step explanation:

cos2θ =  2 cos^2 θ - 1

2cos^2 θ = 1 + cos2θ

cos^2 θ = (1 + cos2θ)/2

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How do you expand (x-10)(x-10)​
denpristay [2]
1 Answer
1.multiply the First terms. x⋅x=x2.
2.multiply the Outside terms. x⋅10=10x.
3.multiply the Inside terms. −10⋅x=−10x.
4.multiply the Last terms. −10⋅10=−100.
5.add all of the answers together. x2+10x−10x−100.
6.combine like terms. x2+10x−10x−100. =x2−100.
4 0
4 years ago
Evaluate<br> 13- (-9)<br><br> need helpp
Viktor [21]

Answer:

The answer is 22.

Explanation:

Multiply -1 by -9.

13 + 9

Add 13 + 9.

22

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>22</u>.

6 0
3 years ago
Solve the system of linear equations. separate the x- and y- values with a coma. 20x=-58-2y
lianna [129]
The best way to solve is by using elimination method.
20x = -58 - 2y
17x = -49 - 2y
Multiply second equation by -1
20x = -58 - 2y
-17x = 49 + 2y
Add equations.
3x = -9 
Divide.
x = -3
Plug in -3 into one of the equations.
17(-3) = -49 - 2y
-51 = -49 - 2y
Add 49 to both sides.
-2 = -2y
Divide.
1 = y
So your solution is (-3, 1).
I hope this helps love! :)

6 0
3 years ago
there are 30 students in a math class of the 30 students 30% have an a in math 40% have a b in math how many students have a c i
stepladder [879]

the answer is 9

30 percent of 30 is 9

40 percent of 30 is 12

12+9 =21

30-21 =9

3 0
3 years ago
Read 2 more answers
Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.
____ [38]

Let z=-\sqrt3+i. Then

|z|=\sqrt{(-\sqrt3)^2+1^2}=2

z lies in the second quadrant, so

\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6

So we have

z=2e^{i5\pi/6}

and the fourth roots of z are

2^{1/4}e^{i(5\pi/6+k\pi)/4}

where k\in\{0,1,2,3\}. In particular, they are

2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}

2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}

2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}

2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}

7 0
3 years ago
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