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schepotkina [342]
2 years ago
8

4. There are 37 students in the class.

Mathematics
2 answers:
ozzi2 years ago
7 0

Answer:

B)1600

Step-by-step explanation:

LenKa [72]2 years ago
4 0

Answer:

2000

Step-by-step explanation:

41 × 37 = 1517

Approximate 1517

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Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29
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Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ \frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

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Now, we have the degree for ∠B= 41°.

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subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

\frac{b}{SinB} = \frac{c}{SinC}

⇒\frac{20}{sin41} = \frac{C}{sin110}

Using the value of sine and cross multiplying both side.

⇒ C= \frac{20\times 0.94}{0.65} = 28.92

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= (15+20+28.92)= 63.9

∴ Perimeter of triangle= 63.9 units

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