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3 years ago

9

Can someone help me with this. Thank you

1 answer:

fomenos3 years ago

4 0

Answer:

horizontal = 5.7

vertical = 8.2

Step-by-step explanation:

Sin(55) = $\frac{cb}{ac} \\$ = 0.82 -> cb = 0.82*10= 8.2

Cos(55) = $\frac{ab}{ac}$ = 0.57 -> ab = 0.57*10 = 5.7

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frutty [35]

Answer:

$x^2+(y-1)^2=1$

Step-by-step explanation:

The given cylindrical equation is

$r=2\sin \theta$

Multiply both sides by r.

$r^2=2r\sin \theta$ .... (1)

The required formulas are

$x=r\cos \theta,y=r\sin \theta,r^2=x^2+y^2$

Substitute $r\sin \theta =y,r^2=x^2+y^2$ in equation (1).

$x^2+y^2=2y$

$x^2+y^2-2y=0$

Add 1 on both sides.

$x^2+(y^2-2y+1)=1$

$(x-0)^2+(y-1)^2=1^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

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Therefore, the equation in rectangular coordinates is $x^2+(y-1)^2=1$ .

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3 years ago

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riadik2000 [5.3K]

Answer:

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Step-by-step explanation:

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2 years ago

El número equivalente de 25/50 por favor

Viefleur [7K]

Answer:

El número equivalente de 25/50 es 1/2

Step-by-step explanation:

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2 years ago

Siri am I a mix of recipe that calls for 1 1/2 cups of flour and 3/4 to get butter Jeremiah uses three sticks of butter how many

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Answer:

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3 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

3 years ago

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