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swat32
3 years ago
11

4^x-3^(x-1/2)=3^(x+1/2)-2^(2x-1)

Mathematics
1 answer:
Natali [406]3 years ago
4 0

Answer:

x = 3/2

Step-by-step explanation:

4^x - 3^{x-1/2} = 3^{x+1/2} - 2^{2x-1}

4^x + 2^{2x-1} = 3^{x+1/2} + 3^{x-1/2}

2^{2x} + 2^{2x-1} = 3^{x+1/2} + 3^{x-1/2}

2^{2x} + 2^{2x} * 2^{-1} = 3^x+ 3^{1/2} + 3^{x} + 3^{-1/2}

2^{2x}(1 + 2^{-1}) = 3^x(3^{1/2} + 3^{-1/2})

2x ln(2) + ln(1 + 2^{-1}) =  x ln(3)  + ln(√3 + 1/√3)

2x ln(2) - x ln(3) = ln(√3 + 1/√3) - ln(1 + 1/2)

x(2ln(2) - ln(3)) = ln(√3 + 1/√3) - ln(1 + 1/2)

x = [ ln(√3 + 1/√3) - ln(1 + 1/2) ] / (2ln(2) - ln(3))

x = 3/2.

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