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umka2103 [35]
3 years ago
10

How to do acid base neutralization reactions work?

Chemistry
1 answer:
melomori [17]3 years ago
7 0
By adding hydrogen ion for cation and OH- for anion if I'm not mistaken.
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An ax is used to chop wood. The metal part chops through the wood, pushing it apart into two smaller sections. which simple mach
Sati [7]
The <span>simple machine found on the head of the  ax is </span>Wedge. A wedge is an inclined plane that can be moved. When an ax is used to split wood, the ax handle exerts a force on the blade of the axe, which is the wedge. That force pushes the wedge down into the wood. The wedge in turn exerts an output force splitting the wood in two. 
3 0
4 years ago
A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder
Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

PV_1=nRT

where,

P = pressure of gas = 1 atm

V_1 = volume of gas = ?

T = temperature of gas = 270^oC=273+270=543K

n = number of moles of gas = 0.205 mol

R = gas constant  = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K

V_1=9.12L

Now we have to calculate the volume at 24°C.

PV_2=nRT

where,

P = pressure of gas = 1 atm

V_2 = volume of gas = ?

T = temperature of gas = 24^oC=273+24=297K

n = number of moles of gas = 0.205 mol

R = gas constant  = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K

V_2=4.99L

Now we have to calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 9.12 L

V_2 = final volume = 4.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (4.99-9.12)L

w=4.13L.artm=4.13\times 101.3J=418.4J

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0
3 years ago
Match with O for organic and I for inorganic for each compound.
Vika [28.1K]

Answer:

Organic compounds: C₃H₆, and C₂H₂.

Inorganic compounds: NaS, SO₂, and HI.

Explanation:

Organic compounds are the molecules that have a carbon backbone with hydrogen atoms in its structure.

While, inorganic molecules are composed of other elements. They can contain hydrogen or carbon, but if they have both, they are organic.

<em>So:</em>

<em>Organic compounds are C₃H₆, and C₂H₂.</em>

<em>Inorganic compounds are NaS, SO₂, and HI.</em>

5 0
3 years ago
MgCl2 + NaOH → Mg(OH)2 +Naci<br> Balance
Oksana_A [137]
MgCl2+2NaOH=Mg(OH)2+2NaCl
3 0
3 years ago
Theobromine (greek theobroma, meaning "food of the gods") is a common constituent in coca. fill in all the lone pairs on each he
Ganezh [65]

The lone pair of electrons in Theobromine are shown in RED color in attached figure.

Details:

           In chemistry there are two types of electrons.

i) Bonding Pair Electrons:

                                        These are those electrons which are being shared and are involved in making bonds. They are also called as sharing electrons. In given structure all the solid bonds either single or double are made up of bonding pair electrons.

ii) Lone Pair / Non-Bonding Pair Electrons:

                                                                     Those electrons which doesn't take part in bonding and are not shared between atoms. In given structure the lone pair of electrons are found only on nitrogen atoms (single lone pair) and oxygen atoms (two lone pair of electrons) respectively.

Hybridization of Nitrogen Atoms;

                                                      N₁  =  Sp²

                                                      N₂  =  Sp³

                                                      N₃  =  Sp³

                                                      N₄  =  Sp³

Hybridization of Oxygen Atoms;

                                                      O₁  =  Sp²

                                                      O₂  =  Sp²

8 0
3 years ago
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