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Lesechka [4]
3 years ago
7

If the abundance of ​ 85​ Rb is 72.2% and the abundance of 87​ Rb is 27.8%, what is the average atomic mass of rubidium?

Chemistry
1 answer:
Kisachek [45]3 years ago
5 0

The average atomic mass of Rubidium : 85.556 u

<h3>Further explanation</h3>

Isotopes are atoms that have the same atomic number but different mass numbers

Each isotope has an abundance which is usually expressed as a percentage

The average relative mass of atoms is obtained by adding the product of the percentage and mass of each isotope

Can be formulated:

\tt Average~Mass~atom~X=mass~isotope~ 1\times \%1+mass~isotope~2\times \%2+..

The abundance of ​ 85​ Rb is 72.2% and the abundance of 87​ Rb is 27.8%, so

mass isotope 1=85, %abundance=72.2

mass isotope 2=87, %abundance=27.8

The averages atomic mass of Rubidium :

\tt average~atomic~mass=85\times 0.722+87\times 0.278\\\\average~atomic~mass=61.37+24.186\\\\average~atomic~mass=\boxed{\bold{85.556~u}}

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4.
telo118 [61]

The series which is in order of increasing boiling point is CH3CH2CH3 CH3COCH3 CH2CH2CH3OH

However, the boiling point of an organic substance is the temperature at which the vapor pressure of the liquid organic substance equals the pressure surrounding the liquid and the liquid changes into a vapor.

<h3>What are organic compounds?</h3>

Organic compounds are substance containing carbon and hydrogen. Some few organic compounds include:

  • Alkanes
  • Alkenes
  • Alkynes
  • Alkanols
  • Alkanals
  • Alkanones
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  • Amines

So therefore, the series which is in order of increasing boiling point is CH3CH2CH3 CH3COCH3 CH2CH2CH3OH

Learn more about organic compounds:

brainly.com/question/704297

8 0
2 years ago
What type of salt will affect temperature most?
vodka [1.7K]

Answer:

Sodium chloride

Explanation:

7 0
3 years ago
Which has a higher boiling point? please help!​
san4es73 [151]
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4 0
4 years ago
In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for
inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)

Reduction at cathode :

Cu^+(aq)+2e^-\rightarrow Cu(s)

Reduction potential of  Cu^{2+} to Cu=E^o_{1}=0.34 V

Oxidation at anode:

Fe(s)\rightarrow Fe^{2+}(aq)+2e^-

Reduction potential of  Fe^{2+} to Fe=E^o_{2}=-0.44 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=0.34V -(-0.44 V)=0.78 V

The standard cell potential of the reaction is 0.78 Volts.

3 0
3 years ago
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