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Vesna [10]
3 years ago
5

A chamber fitted with a piston can be controlled to keep the pressure in the chamber constant as the piston moves up and down to

increase or decrease the chamber volume. The chamber contains an ideal gas at 296 K and 1.00 atm.
What is the work done on the gas as the piston compresses it from 1.00 L to 0.633 L?

Express your answer with the appropriate units.

W =
J
Physics
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

W=37186.275\ J

Explanation:

Given:

isobaric process of a piston cylinder

pressure of the gas in the chamber, P=1\ atm=101325\ Pa

temperature of the gas in the chamber, T_i=296\ K

initial volume of the gas, v_i=10^{-3}\ m^3

final volume of the gas, v_f=0.633\ L=0.633\times 10^{-3}\ m^3

<u>Now the work done is given as:</u>

W=P.(V_i-V_f)

W=101325\times (10^{-3}-0.633\times 10^{-3})

W=37186.275\ J

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A 1232 kg car moving north at 25.6 m/s collides with a 2028 kg car moving north at 17.5 m/s . They stick together. In what direc
Citrus2011 [14]

Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

<u>Given the following data;</u>

Mass of car A = 1232 Kg

Velocity of car A = 25.6 m/s

Mass of car B = 2028 Kg

Velocity of car B = 17.5m/s

First of all, we would solve for momentum;

Momentum = mass × velocity

Momentum, M1 = 1232 × 25.6

Momentum, M1 = 31539.2 Kgm/s

Momentum, M2 = 2028 × 17.5

Momentum, M2 = 35490 Kgm/s

Now, let's find the resultant momentum using the Pythagoras theorem;

R² = M1² + M2²

R² = 31539.2² + 35490²

R² = 994721136.6 + 1259540100

R² = 2254261237

Taking the square root of both sides, we have

Resultant momentum, R = 47479.06 Kgm/s

To find the direction;

Angle = tan¯¹(M1/M2)

Angle = tan¯¹(31539.2/35490)

Angle = tan¯¹(0.89)

<em>Angle = 41.7° Northeast.</em>

To find the speed;

R = (M1 + M2)Vr

47479.06 = (31539.2 + 35490)Vr

47479.06 = 67029.2Vr

Vr = 47479.06/67029.2

<em>Vr = 7.08m/s</em>

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All you have to do is multiply that by the mass or volume.
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