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sergiy2304 [10]
3 years ago
8

Someone please helppp

Physics
1 answer:
aleksklad [387]3 years ago
5 0

okay, so what i have learned from my experiences with doing school on e.d.g.e.n.u.i.t.y (they won't let me say the website name on here lol) is that after you write an extended response, they show you a sample response as well as these checkboxes which show things they wanted you to have included in your answer. ideally they want you to select all of them, meaning that all of those elements were included in your answer. it's not a matter or right or wrong; none of those checkboxes contain a wrong answer. you just select the ones that apply to your answer, and you won't get penalized if you don't select all of the checkboxes. you don't even have to select any of them. there's been times where my answer has been not at all what it should've been and i just click done without checking any of those boxes because i did not include any of those elements in my response. as long as the box that you wrote your answer in is outlined in green (which yours is, and that means that the computer likes your answer), you will be fine.

i hope this makes sense! it's sort of hard to explain. if you have any questions, just comment and i'll try my best to explain better lol. have a great rest of your day! <3

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Answer:

The acceleration of the car is 7.85 m/s²

Explanation:

Given;

vx(t)= (0.910m/s³)t², given time traveled by the car 't' = 5.0 s

⇒To determine the velocity for 5 seconds, we substitute in 5.0 s for t

vx(5)= (0.910m/s³)(5s)²

       = (0.910m/s³)(25s²)

      vx = 22.75 m/s

⇒To determine the acceleration of the car when vx=12.0m/s

Acceleration is change in velocity per unit time

when vx=12.0m/s, our new equation becomes; 12 = (0.910m/s³)t²

Solving for t: t² = 12/0.91

                     t² = 13.187

                      t = √13.187 = 3.63 s

  Acceleration = Δv/Δt

                        = \frac{(22.75 - 12)m/s}{(5-3.63)s} = (\frac{10.75}{1.37}).\frac{m}{s^2}

  Acceleration = 7.85 m/s²

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