H2SO4 ---> 2H^+ + SO4^2-
Hence n H+ = 9 mols
Mass of H = nM = (9*1) = 9g
Alternately
mass of H2SO4= nM= 4.5*98= 441
Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g
Chemical process is responsible for the smell of vinegar in an old bottle of aspirin is Hydrolysis of ester i.e. Aspirin.
Aspirin reacts with water leading to the formation of Acetic acid which is a Carboxylic acid derivative.
Aspirin on Hydrolysis forms Acetic acid and Salicylic acid.
The reaction shows up as a fizz when aspirin is added in water.
Aspirin is called Acetyl Salicylic acid and it helps to reduce:
- Inflammation
- Pain
- Fever
- Headache
- Arthritis
- Muscle pain
- Tooth pain
Acetic acid or Ethanoic acid is a colorless liquid. It is an important carboxylic acid. It smells like vinegar.
Acetic acid is used for production of following:
- Vinyl Acetate
- Insecticides
- Rubber
- Acetic anhydride
Salicylic acid is a bitter compound which is colorless. It reduces acne and opens up the skin pores.
Learn more about Aspirin here, brainly.com/question/23878261
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The reaction is an exothermic reaction and the temperature change is calculated using the formula below:
- Change in temperature = final temperature - initial temperature
<h3>What kind of heat change occurs when anhydrous copper(II) sulfate is dissolved in water?</h3>
When, anhydrous copper(II) sulfate is dissolved in water, heat is given off to the surroundings and the temperature of the solution formed is higher than the temperature of the water used in dissolving it.
This type of reaction is known as an exothermic reaction.
The temperature increase is calculated using the formula below:
- Change in temperature = final temperature - initial temperature
In conclusion, exothermic reactions result in increase in temperature of their surroundings.
Learn more about exothermic reactions at: brainly.com/question/2924714
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Answer:
The sample of lithium occupies the largest volume.
Explanation:
Given the densities for the four elements, we have the expression
that shows the relationship between mass and Volume to express the density of an element.
For each element we have:
![d_{lithium}=\frac{m_{lithium}}{V_{lithium}}=0.53g/mL](https://tex.z-dn.net/?f=d_%7Blithium%7D%3D%5Cfrac%7Bm_%7Blithium%7D%7D%7BV_%7Blithium%7D%7D%3D0.53g%2FmL)
![d_{gold}=\frac{m_{gold}}{V_{gold}}=19.3g/mL](https://tex.z-dn.net/?f=d_%7Bgold%7D%3D%5Cfrac%7Bm_%7Bgold%7D%7D%7BV_%7Bgold%7D%7D%3D19.3g%2FmL)
![d_{aluminum}=\frac{m_{aluminum}}{V_{aluminum}}=2.70g/mL](https://tex.z-dn.net/?f=d_%7Baluminum%7D%3D%5Cfrac%7Bm_%7Baluminum%7D%7D%7BV_%7Baluminum%7D%7D%3D2.70g%2FmL)
![d_{lead}=\frac{m_{lead}}{V_{lead}}=11.3g/mL](https://tex.z-dn.net/?f=d_%7Blead%7D%3D%5Cfrac%7Bm_%7Blead%7D%7D%7BV_%7Blead%7D%7D%3D11.3g%2FmL)
The problem says that all the samples have the same mass, so:
![m_{lithium}=m_{gold}=m_{aluminum}=m_{lead}=m](https://tex.z-dn.net/?f=m_%7Blithium%7D%3Dm_%7Bgold%7D%3Dm_%7Baluminum%7D%3Dm_%7Blead%7D%3Dm)
it means that m is a constant
Now, solving for the Volume in each element and with m as a constant, we have:
![V_{lithium}=\frac{m}{d_{lithium}}](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Blithium%7D%7D)
![V_{lithium}=\frac{1}{0.53\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D%5Cfrac%7B1%7D%7B0.53%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{lithium}=1.88\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D1.88%5Cfrac%7BmL%7D%7Bg%7D%2Am)
![V_{gold}=\frac{m}{d_{gold}}](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Bgold%7D%7D)
![V_{gold}=\frac{1}{19.3\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D%5Cfrac%7B1%7D%7B19.3%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{gold}=5.18*10^{-2}\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D5.18%2A10%5E%7B-2%7D%5Cfrac%7BmL%7D%7Bg%7D%2Am)
![V_{aluminum}=\frac{m}{d_{aluminum}}](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Baluminum%7D%7D)
![V_{aluminum}=\frac{1}{2.70\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D%5Cfrac%7B1%7D%7B2.70%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{aluminum}=3.70*10^{-1}\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D3.70%2A10%5E%7B-1%7D%5Cfrac%7BmL%7D%7Bg%7D%2Am)
![V_{lead}=\frac{m}{d_{lead}}](https://tex.z-dn.net/?f=V_%7Blead%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Blead%7D%7D)
![V_{lead}=\frac{1}{11.3\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Blead%7D%3D%5Cfrac%7B1%7D%7B11.3%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{lead}=8.85*10^{-2}\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Blead%7D%3D8.85%2A10%5E%7B-2%7D%5Cfrac%7BmL%7D%7Bg%7D%2Am)
If we assume m = 1g, we find that:
![V_{lithium}=1.88mL](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D1.88mL)
![V_{gold}=5.18*10^{-2}mL](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D5.18%2A10%5E%7B-2%7DmL)
![V_{aluminum}=3.70*10^{-1}mL](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D3.70%2A10%5E%7B-1%7DmL)
![V_{lead}=8.85*10^{-2}mL](https://tex.z-dn.net/?f=V_%7Blead%7D%3D8.85%2A10%5E%7B-2%7DmL)
So we can see that the sample of lithium occupies the largest volume with 1.88mL
Note that m only can take positive values, so if you change the value of m, always will be the lithium which occupies the largest volume.
Answer:The molar mass of a compound cab be find by adding up all the molar mass of the element present in the compound... Check the image for more clarification
Explanation: