Answer 19.9g. I’ve took the test last week at my uncle randy’s house
Answer:
Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.
<em>Note: Since no specific color was stated for oxygen atoms, the answer assigns blue colored jellybeans to represent oxygen atoms.J</em>
Explanation:
Sodium bicarbonate, NaHCO₃ is a compound composed of one atom of sodium, one atom of hydrogen, one atom of carbon and three atoms of oxygen.
Since red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms and blue jellybeans represent oxygen atoms, each of the two students will require the following number of each jellybean for their model of sodium carbonate: One red jellybean, one white jellybean, one black jellybean and three blue jellybeans.
Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.
Answer:
Explanation:
<em>2. A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?</em>
Notice that I completed the question with the garbled and missing values:
<u>Data:</u>
<u />
<u>Physical principles:</u>
- Newton's second law:

<u>Solution:</u>

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<em>3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?</em>
Notice that I arranged the typos.
<u />
<u>Data:</u>
<u>Physical principles:</u>
- Newton's second law:

<u>Solution:</u>

<em>4. What is the mass of a falling rock if it produces a force of 147 N?</em>
<u>Data:</u>
<u>Physical principles:</u>
- neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²
- Newton's second law:

<u>Solution:</u>
- Clear m from Newton's second law

- Substitute with F = 147 N and a = g = 9.8m/s², and compute

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<em>5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?</em>
<u>Data:</u>
<u>Physical principles:</u>
- Second Newton's law:

<u>Solution:</u>
- Clear m from Newton's second law

- Substitute with F = 14,000 N and a = 5m/s², and compute

A) Initial moles of NH3 = 75/1000 x 0.200 = 0.015 mol
Moles of HNO3 added = 28/1000 x 0.500 = 0.014 mol
NH3 + HNO3 => NH4+ + NO3-
Moles of NH3 left = 0.015 - 0.014 = 0.001 mol
Moles of NH4+ = 0.014 mol
Ka(NH4+) = Kw/Kb(NH3)
= 10-14/1.8 x 10-5 = 5.556 x 10-10
Henderson-Hasselbalch equation:
pH = pKa + log([NH3]/[NH4+])
= -log Ka + log(moles of NH3/moles of NH4+) since volume is the same for both
= -log(5.556 x 10-10) + log(0.0065/0.014)
= 8.14