Ask question

Ask question

All categories

vampirchik [111]

3 years ago

11

Given a collection of paired sample data, the ____________ algebraically describes the relationship between the two variables, x

and y.

1 answer:

NNADVOKAT [17]3 years ago

7 0

Data may be the answer

You might be interested in

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

malfutka [58]

$\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}$

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

$\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}$ $\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}$ $\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}$ $\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}$

Hence, the correct options that apply are options A, D, E and F

7 0

1 year ago

Using pi 3 what is the answer

konstantin123 [22]

Answer:

12mm

Step-by-step explanation:

circumference (distance around) is equal to πd.

here, if π is 3, we do 3 x the diameter, which is 4. 3 x 4 = 12mm

6 0

3 years ago

Find the TWO integers whos product is -12 and whose sum is 1

konstantin123 [22]

Answer:

$\rm Numbers = 4 \ and \ -3.$

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

The sum of two numbers is 1 .
The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x
Second number be 1-x .

<u>According</u><u> to</u><u> </u><u>first </u><u>condition</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}$

<u>Hence </u><u>the</u><u> </u><u>numbers</u><u> </u><u>are </u><u>4</u><u> </u><u>and </u><u>-</u><u>3</u><u> </u>

3 0

3 years ago

Use the card collection box-and-whisker plot to solve.

Klio2033 [76]

The right answer for the question that is being asked and shown above is that: "B.second quarter." Use the card collection box-and-whisker plot to solve.<span> </span><span>In the second quarter that the data are at least concentrated.</span>

4 0

4 years ago

Can someone help me out?

Lera25 [3.4K]

Answer:

so basically

the area of the square; (5cm)^2 = 25cm^5

the area of the triangle; (4cm.5cm)/2 = 10cm^2

which means that r = √25cm^2/10cm^2 = √25/10 cm^2 or √10/25 cm^2

english is not my first language so i do not know what combined means but if u explain a little more i will try to help u

-> ok edit edit;

1cm/5in. = r

5cm => 25in.

z^2= area of a square so

25in.25in= 625 in^2

4cm => 20in.

5cm => 25in.

h.b/2 = area of a triangle so

20in.25in./2 = 250in.^2

250in.^2 + 625in.^2 = 875in.^2

so answer B

5 0

3 years ago

Read 2 more answers