B because you can see the elements being swapped by the other elements on both sides of the equation, please mark me as Brainlliest
The positively charged atmosphere attracts negatively charged spider silk, might electrostatic force play in spider dispersal, according to a recent study.
Answer: Option C
<u>Explanation:</u>
The positive charge present in upper of the atmosphere and the negative charge on planet’s surface. During cloudless skies days, the air possesses a voltage of nearly around 100 volts for each and every meter from above the ground.
Ballooning spiders process within this planetary electric field. When their silk relieve their bodies then it picks up a negative charge. This oppose the similar negative charges on the surfaces on which the spiders settles and create sufficient force to lift them into the air. And spiders can hike those forces by climbing onto blades of grass,twigs, or leaves.
To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.
From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:
Where
input voltage on the primary coil.
input voltage on the secondary coil.
number of turns of wire on the primary coil.
number of turns of wire on the secondary coil.
Replacing our values we have:
Replacing,
From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:
Where
= Current Primary Coil
= Current secundary Coil
Therefore:
Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A
I think that ball a hit the ground because it says that it went straight down.
Answer:
20 V
Explanation:
Power is 100 J/s or 100 W.
We know that P = IV = 
.
Isolate the potential difference. V = 
= 
= 20 V
