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3 years ago

What does invading the host cell enable the virus to do?

Physics

1 answer:

ddd [48]3 years ago

4 0

Answer:

D) reproduce

Explanation:

When a virus invades a host cell, it simply enables the virus to reproduce by replicating several copies of its genetic materials.

Viruses have no life outside of a host cell, however, they come to life when they enter a living host cell.

In the host cell, they simply utilize the resources of the cell to make several copies of their own.

Viruses are parasites that are very harmful to all living cells.

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A 100-g aluminum calorimeter contains 500 g of water at a temperature of 20ºC. Then a 140-g piece of metal, initially at 344ºC,

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3 years ago

John is riding the bus to the next samuell football game. The bus is traveling to the right at 20 m/s and Jon is walking towards

Elenna [48]

Answer:

Vrel_jon's = 15 [m/s] to the right

Explanation:

Relative velocity is defined as the relative motion between two bodies, taking into account the directions of motion.

Relative velocity is defined as the relative motion between two bodies, taking into account the directions of motion. The relative velocity is defined as the algebraic sum of the velocities, if the movements are opposite the vectors are subtracted, as will be done below.

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3 years ago

An object with a mass of 0. 25 kg is undergoing simple harmonic motion at the end of a vertical spring with a spring constant, k

skelet666 [1.2K]

Answer:

1) The amplitude of the motion is approximately 0.274 meters.

2) The total energy of the object at any point of its motion is 16.892 joules.

Explanation:

1) An object under simple harmonic motion is conservative, since there is no dissipative forces acting during motion (i.e. friction, air viscosity). The amplitude of the motion can be found easily by Principle of Energy Conservation by the fact that maximum elastic potential energy ( $U_{e}$ ), in joules, is equal to maximum translational kinetic energy ( $K$ ), in joules:

$U_{e} = K$

$\frac{1}{2}\cdot k \cdot A^{2} = \frac{1}{2}\cdot m \cdot v^{2}$ (1)

Where:

$k$ - Spring constant, in newtons per meter.

$A$ - Amplitude, in meters.

$m$ - Object mass, in kilograms.

$v$ - Speed of the object at equilibrium, in meters per second.

If we know that $k = 450\,\frac{N}{m}$ , $m = 0.25\,kg$ and $v = 0.3\,\frac{m}{s}$ , then the amplitude of the motion is:

$\frac{1}{2}\cdot k \cdot A^{2} = \frac{1}{2}\cdot m \cdot v^{2}$

$k\cdot A^{2} = m\cdot v^{2}$

$A = v\cdot \sqrt{\frac{m}{k} }$

$A = \left(0.3\,\frac{m}{s} \right)\cdot \sqrt{\frac{0.25\,kg}{0.3\,\frac{m}{s} } }$

$A \approx 0.274\,m$

The amplitude of the motion is approximately 0.274 meters.

2) The total energy of the object ( $E$ ), in joules, is found either by maximum elastic potential energy or by maximum translational kinetic energy, that is: ( $k = 450\,\frac{N}{m}$ , $A \approx 0.274\,m$ )

$E = U_{e}$

$E = \frac{1}{2}\cdot k\cdot A^{2}$

$E = \frac{1}{2}\cdot \left(450\,\frac{N}{m} \right) \cdot (0.274\,m)^{2}$

$E = 16.892\,J$

The total energy of the object at any point of its motion is 16.892 joules.

7 0

3 years ago