Hi there!
Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:
Wsinθ = downward acceleration along incline due to gravity (N)
Fκ = kinetic friction force along incline (N)
A = applied force (N)
The acceleration due to gravity and friction force act in the same direction, so:
Wsinθ + Fκ = A
Solve for sinθ using right triangle trigonometry:
sinθ = O/H = 3/6 = 0.5
Rearrange the equation for the force of kinetic friction and solve:
Fκ = A - 0.5W
Fκ = 30.4 - 20 = 10.4 N
Now, recall that:
Work = Force × displacement (W = F × d)
Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:
W = Fdcosθ
Angle between displacement and friction force is 180°.
cos(180) = -1
Work done by friction = -Fd = -10.4(6) = -62.4 J
Answer:
5.6
Explanation:
F=kx is the formula for spring force. If Extension versus Force was graphed, a linear relation would appear, where the slope is the k value, aka the spring constant.
Answer:
We usually travel in January or Feb for our tropical get-a-way. For those of you that have traveled in the fall and winter...
What is the real difference...Like in the floral and fauna, weather, and the capacity of the resorts between these 2 times of the year.
Explanation:
It is given that,
Weight of the rock in air, W = 110 N
Since, W = mg
m = 11.22 kg
We need to find the apparent weight of the rock when it is submerged in water. Apparent weight is equal to the weight of liquid displaced i.e.
d is the density of water, 
V is the volume of rock, 
M = 3.37 kg
The apparent weight in water, W = m - M
W = 76.93 N
So, the apparent weight of the rock is 76.93 N. Hence, this is the required solution.
Potassium undergoes beta (minus) decay to produce an electron and a calcium nucleus.
