Only 6 out of 75 trees in the park are at least 30 feet tall. what percen of the trees are under 30 feet tall

LCM of two numbers is 1134 and HCF is 18. if one of the numbers is 162, find the other. number.

Brilliant_brown [7]

<h3>Answer: 126</h3>

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Work Shown:

Let x and y be the two numbers.

We're given x = 162 and the variable y is unknown.

We're also given LCM = 1134 and HCF = 18

So,

LCM = (x*y)/HCF

1134 = 162*y/18

1134 = (162/18)y

1134 = 9y

9y = 1134

y = 1134/9

y = 126

The other number is 126

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Notice that

162 = 18*9
126 = 18*7

showing that 18 is the highest common factor (HCF) of the numbers 162 and 126. This partially confirms the answer.

Now let,

A = multiples of 162
B = multiples of 126

So,

A = 162, 324, 486, 648, 810, 972, 1134, 1296, ...
B = 126, 252, 378, 504, 630, 756, 882, 1008, 1134, 1260, ...

We see that 1134 is in each list of multiples and the smallest such common item. So the lowest common multiple (LCM) of 162 and 126 is 1134. This helps fully confirm the answer.

7 0

2 years ago

A car moves at a constant speed of 90km/h from a starting point. Another car moves at 70km/h after 2hours from the same starting

patriot [66]

Step-by-step explanation:

are you sure you wrote the problem here correctly ?

because the distance will be 40km after less than half an hour just by the first car driving. way before the second car even starts.

to be precise, it would be after 60 minutes × 40 / 90

(= how many minutes of an hour are needed to reach 40km while going 90km/h) :

60 × 40 / 90 = 60 × 4 / 9 = 20 × 4 / 3 = 80/3 = 26.67 minutes.

but maybe the question was about 400km distance between the two cars.

so, the first car goes 90km/h for 2 hours.

at that moment it will be 2×90=180km ahead.

that would mean that 220km are still missing for the 400km assumption.

with each hour driving the first car makes 20km more than the second car.

to build up 220km that way would require

220/20 = 11 hours.

plus the 2 original head start hours this would make 13 hours as overall answer.

7 0

2 years ago

Aahil, James and merav share £90 in the ratio 1:3:5 how much does merav get

Dafna1 [17]

Given: £90 is divided among Aahil, James and Merav in the ratio 1:3:5.

To find: How much Merav gets.

Answer:

Let's assume the shares of each to be 'x'.

This implies that 1x + 3x + 5x = 90.

9x = 90

x = 90/9

x = 10

Substituting this value of x in the ratio,

1 × 10 = 10 [Aahil's share]
3 × 10 = 30 [James' share]
5 × 10 = 50 [Merav's share]

Therefore, Merav gets £50.

Hope it helps. :)

8 0

2 years ago

Select the correct product. (x 2 + 4x + 8)(2x - 1)

marusya05 [52]

Answer:

$\large\boxed{(x^2+4x+8)(2x-1)=2x^3+7x^2+12x-8}$

Step-by-step explanation:

Use FOIL: (a + b)(c + d) = ac + ad + bc + bd

$(x^2+4x+8)(2x-1)\\\\=(x^2)(2x)+(x^2)(-1)+(4x)(2x)+(4x)(-1)+(8)(2x)+(8)(-1)\\\\=2x^3-x^2+8x^2-4x+16x-8\qquad\text{combine like terms}\\\\=2x^3+(-x^2+8x^2)+(-4x+16x)-8\\\\=2x^3+7x^2+12x-8$