Answer:
B. 4 Fe + 3 0₂---> 2 Fe₂O3
Explanation:
(A) Ir + O₂--> IrO₂ No: Ir is iridium
(B) 4 Fe + 3 0₂---> 2 Fe₂O3 Yes: Fe is iron and O is oxygen, and the equation is balanced.
(C) I+ 0₂ ---> 10₂ No: I is iodine
(D) 3 Ir + 0₂ -> 6 Ir₂03 No: I is iodine
Answer:
The reaction that occurs is a redox reaction. The Copper metal (Cu 0)on the copper pennies is oxidized in concentrated nitric acid to produce Cu2+ ions. Copper is easily oxidized to Cu2+, which is blue in aqueous solutions (water) so you should see the solution turn blue as the copper penny reacts.
Have a nice day ;)(^-^)
CaI₂ + Hg(NO₃)₂ --------->HgI₂ + Ca(NO3)2
2Al + 3Cl₂ --------->2AlCl3
Ag + HCl ------->AgCl + H2
C2H2 + 5O2 --------> 4CO2 + 2H2O
MgCl₂ --------->Mg + Cl2
Answer:
No it is not balanced
Explanation:
CaCl2 + 2NaHCO3 → CO2 + CaCO3 + H2O + 2NaCl
Hope this helps
Answer:
1) B
2) D
3) A
4) Ga
5) K
6)Po
7) Atomic size increases down the group
8) B<Al<Ga<In<Tl
9)Se<C<Ga
10) ionization energy is the energy required to remove electrons from the outermost shell of an atom.
Explanation:
In the periodic table, the properties of elements reoccur ''periodically'' throughout the table, hence the name 'periodic table'.
Ionization energy increases across the period hence the noble gas He has the highest ionization energy.
Since ionization energy increases across the period, group 1 elements possess the lowest ionization energy.
Since atomic size increases down the group and decreases across the period, gallium is smaller than indium, potassium is smaller than caesium, polonium is smaller than titanium and iodine is larger than bromine.
This explanation above justifies the order of increasing atomic radius of group 13 elements shown in answer number 8 above.
Since atomic size decreases across the period, the order of increasing atomic size shown in answer number 9 above is correct.
Ionization energy is the energy required to remove electrons from the outermost shell of an atom.
