Answer:
x = 1474.9 [m]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.
We must understand that when forces are applied on the body, they tend to slow the body down to stop it.
So as the body continues to move to the left, it is slowing down. Therefore we must calculate this deceleration value using Newton's second law. We must perform a sum of forces on the x-axis equal to the product of mass by acceleration. With leftward movement as negative and rightward forces as positive.
ΣF = m*a
Now using the following equation of kinematics, we can calculate the distance of the block, before stopping completely. The initial speed must be 100 [m/s].
where:
Vf = final velocity = 0 (the block stops)
Vo = initial velocity = 100 [m/s]
a = - 3.39 [m/s²]
x = displacement [m]
Answer:
This structure can be viewed as consisting of six separate parts: (1) a nucleus, (2) a central bulge, (3) a disk (both a thin and a thick disk), (4) spiral arms, (5) a spherical component, and (6) a massive halo. Some of these components blend into each other. Three views of the Milky Way Galaxy.
Explanation:
Answer:
I know 1, that is in the case of a burning of a candle.
Explanation:
Answer:
Explanation:
From the given information, we are to compare the minimum energies required to remove a neutron from , and
To start with ; the minimum energy required to remove a neutron from is :
=
= (38156.36 - 37225.15 -939.57) MeV
= -8.36 MeV Since energy is being given out
Thus, E = 8.36 MeV
the minimum energy required to remove a neutron from is :
=
= ( 39084.46 - 38156.36 - 939.57) MeV
= -11.47 MeV Since energy is being given out
Thus, E = 11.47 MeV
the minimum energy required to remove a neutron from is :
=
= (40016.10 -39084.46 -939.57) MeV
= - 7.93 MeV Since energy is being given out
Thus, E =7.93 MeV
Why there is a distinct increase of this energy for ?
This is as a result of electronic configuration of which posses the same number of proton and neutron, as such, tends to acquire more stability. For this reason, it will be difficult to remove a neutron from .