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Elenna [48]
3 years ago
11

Can someone help me plz

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
8 0
-4.25 because that is the only number out of those options between -4 and -5
s2008m [1.1K]3 years ago
5 0
The second choice bc it can be plotted between-4 and -5 and is a rational number
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Tangent line i think please help me find x
Alex

Answer:

x= 6.5 cm

Step-by-step explanation:

When a tangent line touches the circle, it forms a right angle triangle at that point

Apply the Pythagorean relationship in this case

Given that the height is = 20.2 cm = b

The hypotenuse is = c= x+14.7 cm

General formulae is;

a² +b² =c²

x² + 20.2² =( x+ 14.7)²

x² + 408.04= x² +14.7x+14.7x+216.09

x² + 408.04= x² + 29.4 x +216.09.........................collect like terms

x²-x² + 408.04-216.09= 29.4x

191.95= 29.4x-------------------------------divide by 29.4 t0 get x

191.95/29.4 =x

x=6.5 cm

6 0
3 years ago
A total of 691 tickets were sold for the school play they were either adult tickets or student tickets there were fifty nine few
garri49 [273]
691 = A+ S
A=S+59
691 = S+59+S
691=2S+59
691-59 = 2S +59 -59
632 = 2S
316= S
5 0
3 years ago
True or False <br> If an acute angle is 80o then we add the obtuse angle of 110o to equal 180o?
DIA [1.3K]

Answer:

true

Step-by-step explanation:

5 0
2 years ago
Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
-Dominant- [34]

Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

  • The sample means are: \mu_A = 8.65, \mu_B = 11.23
  • The standard deviations for the samples are s_A = s_B = 0.67

Hence, the standard errors are:

s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58

s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

t = 2.12

The critical value for a <u>right-tailed test</u>, as we are testing if the subtraction is greater than a value, with a <u>0.05 significance level</u> and 12 + 12 - 2 = <u>22 df</u> is given by t^{\ast} = 1.71

Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0
3 years ago
Solve for a 4/a+4= -1/a+9
Karolina [17]

Answer:

a = -8

Step-by-step explanation:

4/a + 4 = -1/a + 9

-1(a + 4) = 4(a + 9)

-1a - 4 = 4a + 36

-5a - 4 = 36

-5a = 40

a = -8

7 0
3 years ago
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