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Paladinen [302]
3 years ago
10

Calculate the molarity of a solution made by 1,5kg of K. CO₂ in 850 mL of water.

Chemistry
1 answer:
anastassius [24]3 years ago
8 0

Answer:

17.83M

Explanation:

Given parameters:

Mass of KCO₂ = 1.5kg

Volume of water  = 850mL

Unknown:

Molarity of solution  = ?

Solution:

Molarity is defined as the number of moles per unit volume. It is the number of moles of solute in a given volume of solution.

   Molarity  = \frac{number of moles }{volume}

Number of moles of solute  = \frac{mass of KCO_{2} }{molar mass}

  Molar mass of KCO₂  = 39 + 12 + 3(16) = 99g/mol

  Number of moles  = \frac{1500}{99}   = 15.15moles

   850mL : gives 0.85L

     

Molarity  = \frac{15.15}{0.85}   = 17.83M

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4) A granola bar has a mass of 42.9 g and the granola bar contains 26.20% honey
nata0808 [166]

<u>Answer:</u>

The percentage of honey in one granola bar is 26.02 percent.  

<u>Explanation:</u>

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Now the amount of honey in the factory is given as 189.5g the weight of total granola bars would be

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3 years ago
Determine which compound would raise the boiling point of water the most
umka2103 [35]
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3 years ago
Consider the reaction 2 NO + O2 → 2 NO2
Sonbull [250]

Answer:

(a) Rate at which NO_2 is formed is 0.050 M/s

(b) Rate at which O_2 is consumed is 0.0250 M/s.

Explanation:

The given reaction is:-

2NO+O_2\rightarrow 2NO_2

The expression for rate can be written as:-

-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}

Given that:- \frac{d[NO]}{dt}=-0.050\ M/s (Negative sign shows consumption)

-\frac{1}{2}\frac{d[NO]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}

-\frac{d[NO]}{dt}=\frac{d[NO_2]}{dt}

-(-0.050\ M/s)=\frac{d[NO_2]}{dt}

\frac{d[NO_2]}{dt}=0.050\ M/s

(a) Rate at which NO_2 is formed is 0.050 M/s

-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}

-\frac{1}{2}\times -0.050\ M/s=-\frac{d[O_2]}{dt}

\frac{d[O_2]}{dt}=0.0250\ M/s

(b) Rate at which O_2 is consumed is 0.0250 M/s.

5 0
3 years ago
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