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Paladinen [302]
3 years ago
10

Calculate the molarity of a solution made by 1,5kg of K. CO₂ in 850 mL of water.

Chemistry
1 answer:
anastassius [24]3 years ago
8 0

Answer:

17.83M

Explanation:

Given parameters:

Mass of KCO₂ = 1.5kg

Volume of water  = 850mL

Unknown:

Molarity of solution  = ?

Solution:

Molarity is defined as the number of moles per unit volume. It is the number of moles of solute in a given volume of solution.

   Molarity  = \frac{number of moles }{volume}

Number of moles of solute  = \frac{mass of KCO_{2} }{molar mass}

  Molar mass of KCO₂  = 39 + 12 + 3(16) = 99g/mol

  Number of moles  = \frac{1500}{99}   = 15.15moles

   850mL : gives 0.85L

     

Molarity  = \frac{15.15}{0.85}   = 17.83M

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Answer:

Here's what I get  

Explanation:

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According to Le Châtelier's Principle, when we apply a stress to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

If you add Ag⁺ to the equilibrium solution, it removes the SCN⁻ [as an Ag(SCN) precipitate].

The system responds by trying to replace the missing SCN⁻:

The Fe(SCN)²⁺ dissociates to form SCN⁻, so the position of equilibrium shifts to the left,

You now have more Fe³⁺ and SCN⁻ and less of the highly coloured Fe(SCN)²⁺ at the new equilibrium.

The deep red colour becomes less intense.

 

3 0
3 years ago
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Answer:

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Explanation: SOLUTION

GIVEN

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4 0
3 years ago
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Answer:

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