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azamat
3 years ago
14

Did an oxidation-reduction reaction occur in the reaction between copper sulfate and sodium sulfide?

Chemistry
2 answers:
salantis [7]3 years ago
7 0

1. It's not gonna be A, B, or C because  redox means when the electrons transfer both ways and a b and c dont show that. Bw d and E i'd go for D.

for 2.

I'd say B  because both reactants are acqueous while 1 product is solid so it would probably precipitate.



good luck dadddddd

azamat3 years ago
5 0

<em>Redox question </em>

Answer:

D. This is not a redox reaction because no electrons were transferred.

<em>Explanation</em>:

We can check whether a reaction is a redox reaction by determining the oxidation number of each atom on both sides of the arrow.

\stackrel{\hbox{+2}}{\hbox{Cu}}\stackrel{\hbox{+6}}{\hbox{S}}\stackrel{\hbox{-2}}{\hbox{O}}_{4} + \stackrel{\hbox{+1}}{\hbox{Na }}_{2}\stackrel{\hbox{-2}}{\hbox{S}} \longrightarrow \stackrel{\hbox{+2}}{\hbox{Cu}}\stackrel{\hbox{-2}}{\hbox{S}} + \stackrel{\hbox{+1}}{\hbox{Na}}_{2}\stackrel{\hbox{+6}}{\hbox{S}}\stackrel{\hbox{-2}}{\hbox{O}}_{4}

The oxidation number does not change for <em>any</em> atom, so this is not a redox reaction.


<em>Precipitation question </em>

Answer:

B.  CdSO₄(aq) + K₂S(aq) → CdS(s) + K₂SO₄(aq)

Explanation:

A precipitation reaction occurs when an insoluble solid forms from the reaction of two substances in a solution.

This is the only reaction that forms a solid from two soluble reactants.

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Answer:

<u></u>

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Explanation:

Since sulfuric acid, H₂SO₄, is a diprotic acid and potassum hydroxide, KOH, contains one OH⁻ in the formula, the number of moles of potassium hydroxide must be twice the number of moles of sulfuric acid.

<u>1. Determine the number of moles of KOH in 47mL of 0.39M potassium hydroxide solution</u>

  • number of moles = molarity × volume in liters
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<u>3. Determine the concentration that contains 0.009165 mol in 25mL of the acid.</u>

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  • M = 0.009165mol/(25mL) × (1,000mL/liter) = 0.3666M

Round to two significant figures: 0.37M

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