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azamat
3 years ago
14

Did an oxidation-reduction reaction occur in the reaction between copper sulfate and sodium sulfide?

Chemistry
2 answers:
salantis [7]3 years ago
7 0

1. It's not gonna be A, B, or C because  redox means when the electrons transfer both ways and a b and c dont show that. Bw d and E i'd go for D.

for 2.

I'd say B  because both reactants are acqueous while 1 product is solid so it would probably precipitate.



good luck dadddddd

azamat3 years ago
5 0

<em>Redox question </em>

Answer:

D. This is not a redox reaction because no electrons were transferred.

<em>Explanation</em>:

We can check whether a reaction is a redox reaction by determining the oxidation number of each atom on both sides of the arrow.

\stackrel{\hbox{+2}}{\hbox{Cu}}\stackrel{\hbox{+6}}{\hbox{S}}\stackrel{\hbox{-2}}{\hbox{O}}_{4} + \stackrel{\hbox{+1}}{\hbox{Na }}_{2}\stackrel{\hbox{-2}}{\hbox{S}} \longrightarrow \stackrel{\hbox{+2}}{\hbox{Cu}}\stackrel{\hbox{-2}}{\hbox{S}} + \stackrel{\hbox{+1}}{\hbox{Na}}_{2}\stackrel{\hbox{+6}}{\hbox{S}}\stackrel{\hbox{-2}}{\hbox{O}}_{4}

The oxidation number does not change for <em>any</em> atom, so this is not a redox reaction.


<em>Precipitation question </em>

Answer:

B.  CdSO₄(aq) + K₂S(aq) → CdS(s) + K₂SO₄(aq)

Explanation:

A precipitation reaction occurs when an insoluble solid forms from the reaction of two substances in a solution.

This is the only reaction that forms a solid from two soluble reactants.

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elena-s [515]

Answer:

A. air expands when heated.

Explanation:

hope this helps!

4 0
3 years ago
In general, atmospheric pressure is greatest near Earth's surface and ____ as you move upward away from sea level.
sweet-ann [11.9K]
Decreases, when you move upward and increases moving in due to various forces like gravity
6 0
3 years ago
How many moles are there in 987 grams of Ra(OH)2? id also love to know the simplest equation for converting moles --&gt; so i co
OlgaM077 [116]
Mole = \frac{mass}{molar mass}

Mass of Radium Hydroxide = 987g
Molar Mass of Ra(OH) _{2} = ((226) + (2 * 16) + (2 * 1))
                                            =  260 g / mol

∴  Moles of <span>Ra(OH) _{2} = </span>\frac{987 g }{ 260 g / mol }
                                            = 3.796 mols
6 0
3 years ago
A civil engineering student is considering buying an electric car. However, the conscious student wants to make sure her carbon
svetlana [45]

Answer:

\text{An gasoline-powered vehicle has }\\\boxed{\text{five times the carbon footprint}}\text{ of an electric vehicle.}

Explanation:

1. Miles travelled in an average month  

\text{Miles} = \text{1 mo} \times \dfrac{\text{52 wk}}{\text{12 mo}} \times \dfrac{\text{5 da}}{\text{1 wk}} \times \dfrac{\text{16 mi}}{\text{1 da}} = \text{347 mi}

2. Using a gasoline powered vehicle  

(a) Moles of heptane used  

n = \text{347 mi} \times \dfrac{\text{1 gal}}{\text{36.5 mi}}\times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{679.5 g}}{\text{1L}} \times \dfrac{ \text{1 mol}}{\text{100.20 g}}= \text{244 mol}

(b) Equation for combustion  

C₇H₁₆ + O₂ ⟶ 7CO₂ + 8H₂O  

(c) Moles of CO₂ formed  

n = \text{244 mol heptane} \times \dfrac{\text{7 mol CO$_{2}$}}{\text{1 mol heptane}} = \text{1710 mol CO$_{2}$}

(d) Volume of CO₂ formed  

At 20 °C and 1 atm, the molar volume of a gas is 24.0 L.  

V = \text{1710 mol } \times \dfrac{\text{24.0 L}}{\text{1 mol}} \times \dfrac{\text{1 gal}}{\text{3.785 L}} = \textbf{10 800 gal}

3. Using an electric vehicle  

(a) Theoretical energy used  

\text{Theor. Energy} = \text{347 mi} \times \dfrac{\text{1 kWh}}{\text{5.2 mi}} = \text{66.7 kWh theor.}

(b) Actual energy used  

The power station is only 85 % efficient.  

\text{Actual energy used} = \text{66.7 kWh theor.} \times \dfrac{\text{100 kWh actual}}{\text{ 85 kWh theor.}}\times \dfrac{\text{3600 kJ}}{\text{1 kWh}}\\\\ = 2.82\times 10^{5} \text{ kJ}\

(c) Combustion of CH₄

CH₄ + 2O₂ ⟶ CO₂ +2 H₂O

(d) Equivalent volume of CO₂

The heat of combustion of methane is -802.3 kJ·mol⁻¹  

V= 2.82\times 10^{5}\text{ kJ} \times \dfrac{\text{1 mol methane}}{\text{802.3 kJ}} \times \dfrac{\text{1 mol CO$_{2}$} }{\text{1 mol methane}} \times \dfrac{ \text{24.0 L}}{ \text{1 mol CO$_{2}$}}\\\\ \times \dfrac{\text{1 gal}}{\text{3.875 L}} = \textbf{2180 gal}

4. Comparison  

\dfrac{V_{\text{gasoline}}}{V_{\text{electric}}} = \dfrac{10800}{2180} = 5.0\\\\ \text{An gasoline-powered vehicle has }\\ \boxed{\textbf{ five times the carbon footprint}}\text{ of an electric vehicle.}

6 0
3 years ago
When iron rusts in air iron3 oxide is produced. How many moles of oxygen react with 28.0 mol of iron in the rusting reaction 4fe
Marrrta [24]
This the balanced equation based on the question 4Fe + 3O_2  -\ \textgreater \ 2Fe_2O_3.

We then proceed with the following calculations

28.0molFe*(\frac {3molO_2}{4mol Fe})= 21molO_2

The answer is 21molO_2 is produced.
5 0
3 years ago
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