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ELEN [110]
3 years ago
10

How many H atoms are there in 1 mol of water?

Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
7 0
There is 2 hydrogen atoms in 1 mol of water. H2O*
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A 30ml sample of a liquid has a mass of 50 grams. What is the density of the liquid?
mash [69]

Answer:

<h2>Density = 1.67 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 50 g

volume = 30 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{50}{30}  \\  =  \frac{5}{3}  \\  = 1.66666...

Wr have the final answer as

<h3>Density = 1.67 g/mL</h3>

Hope this helps you

5 0
3 years ago
Pleasee help <br> will name brainliest
zmey [24]

Answer:

0.125. work- divide the volume value by 1000

873. work- multiply the length value by 100

98100. work- Conversion factor: 1 kg = 100000 cg

1) Centigram = Kilogram * 100000

2) Centigram = 0.981 * 100000

3) Centigram = 98100

285.65. work- 12.5°C + 273.15 = 285.65K

446.85. work- 720K − 273.15 = 446.85°C

346.25. work- 73.1°C + 273.15 = 346.25K

Explanation:

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8 0
3 years ago
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Phantasy [73]

Answer:

c the pressure increases

5 0
3 years ago
ammonium bromide reacts with copper(i) sulfate in aqueous solution to form a solid precipitate. what is the net ionic equation f
sukhopar [10]

Answer:

Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)

Explanation:

Hello,

In this case, the molecular chemical reaction is written as:

2NH_4Br(aq)+Cu_2S(aq)\rightarrow 2CuBr(s)+(NH_4)_2SO_4(aq)

In such a way, considering the net ionic notation and the solid yielded copper (I) bromide, we write:

2NH_4^+(aq)+Br^-(aq)+Cu^+(aq)+SO_4^{2-}(aq)\rightarrow CuBr(s)+NH_4^+(aq)+SO_4^{2-}(aq)

Whereas ammonium and sulfate ions are spectator ions, therefore the net ionic equation is:

Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)

Regards.

5 0
3 years ago
A sample of gas has a volume of 1.40 L at a pressure of 225 mmHg. What is the new volume at a pressure of 515 mmHg?
guajiro [1.7K]

Answer:0.61L

Explanation:

P1V1/n1T1=P2V2/n2T2

n1=n2 T1=T2

Therefore;

P1V1=P2V2

225×1.4=515×V2

V2=0.61L

N.B: Increase in pressure leads to decreases in volume (Boyle's law)

5 0
3 years ago
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