All categories

3 years ago

Which index fossil is most likely to be found in the Allegheny Plateau?

Chemistry

1 answer:

Usimov [2.4K]3 years ago

5 0

Answer:

amphibians

Explanation:

please mark this answer as brainliest

You might be interested in

A compound has a molar mass of 90. grams per mole and the empirical formula CH2O. What is the molecular formula of this compound

k0ka [10]

Answer:

C₃H₆O₃

Explanation:

Data:

EF = CH₂O

MM = 90. g/mol

Calculations:

EF Mass = (12.01 + 2.016 + 16.00) u = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

$n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{90. u}}{\text{30.03 u}} = 3.00 \approx 3$

MF = (CH₂O)₃ = C₃H₆O₃

7 0

3 years ago

Quais serras que se destacam no planalto sul amazonico?

Vladimir79 [104]

Brazil ...............

7 0

3 years ago

A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your

amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{Volume in liter}}$

Also, when number of moles are equal in a solution then the formula will be as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

It is given that $M_{1}$ is 8.00 M, $V_{1}$ is 7.00 mL, and $M_{2}$ is 0.80 M.

Hence, calculate the value of $V_{2}$ using above formula as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

$8.00 M \times 7.00 mL = 0.80 M \times V_{2}$

$V_{2} = \frac{56 M. mL}{0.80 M}$

= 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.

7 0

3 years ago

An object with a mass of 5.0 kg accelerates 8.0 m/s2 when an unknown force is applied to it. What is the amount of the force?

atroni [7]

The correct amount of force i believe is
f= 40 newton
i got the answer by using the formula below
force = mass x acceleration
f=5kg *8.0 m/s^2

7 0

3 years ago

The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh

Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

$3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ$

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

$Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ$

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

$150.0 mL \times \frac{1.02g}{mL} = 153 g$

Given the specific heat capacity of the solution (c) is 4.184 J/g･°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

$Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J }{\frac{4.184J}{g.\° C } \times 153g} = 5.87 \° C$

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0

2 years ago