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Vesna [10]
3 years ago
12

Community Gym Charges a $50 membership fee and a $55 monthly fee. Workout Gym charges a $200 membership fee and a $45 monthly fr

e. How many months will the total amount of money paid to both gyms be th same? What will the amount be?
Mathematics
1 answer:
zheka24 [161]3 years ago
3 0
For the Community Gym:
Membership Charge = $50
Monthly fee = $55
So for the 1st month total charge = $(50 +55)
                                                       = $105
For each month the member pays $55
So after the 2nd month total payment = $(105 + 55)
                                                             = $160
After 3rd month total payment = $(160 + 55)
                                                 = $215
After 4th month total payment = $(215 + 55)
                                                 = $270
After 5th month total payment = $(270 + 55)
                                                 = $325
After 6th month total payment = $(325 + 55)
                                                 = $380
Now for the Workout Gym:
Membership Charge = $200
Monthly Charge = $45
So for the 1st month the member pays = $(200 + 45)
                                                                = $245
For the 2nd month total payment = $( 245 +45)
                                                      = $290
For the 3rd month total payment = $(290 + 45)
                                                     = $335
For the 4th month total payment = $(335 + 45)
                                                     = $ 380
So the 6th month payment in the Community Gym is the same as the 4th month payment in the Workout Gym. The amount will be $380.
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In a G.P the 3rd term is 4 times the 1st term and the sum of the 2nd term and the 4th term is 30.find the common ratio,find the
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Answer:

the common ratio is either 2 or -2.

the sum of the first 7 terms is then either 765 or 255

Step-by-step explanation:

a geometric sequence or series of progression (these are the most common names for the same thing) means that every new term of the sequence is created by multiplying the previous term by a constant factor which is called the common ratio.

so,

a1

a2 = a1×f

a3 = a2×f = a1×f²

a4 = a3×f = a1×f³

the problem description here tells us

a3 = 4×a1

and from above we know a3 = a1×f².

so, f² = 4

and therefore the common ratio = f = 2 or -2 (we need to keep that in mind).

again, the problem description tells us

a2 + a4 = 30

a1×f + a1×f³ = 30

for f = 2

a1×2 + a1×2³ = 30

2a1 + 8a1 = 30

10a1 = 30

a1 = 3

for f = -2

a1×-2 + a1×(-2)³ = 30

-10a1 = 30

a1 = -3

the sum of the first n terms of a geometric sequence is

sn = a1×(1 - f^(n+1))/(1-f) for f <>1

so, for f = 2

s7 = 3×(1 - 2⁸)/(1-2) = 3×-255/-1 = 3×255 = 765

for f = -2

s7 = -3×(1 - (-2)⁸)/(1 - -2) = -3×(1-256)/3 = -3×-255/3 =

= -1×-255 = 255

4 0
3 years ago
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