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Nuetrik [128]
2 years ago
5

You have 2/3 of sugar how muck sugar will you use if you makes 6 batches of cookies

Mathematics
1 answer:
zalisa [80]2 years ago
4 0

Answer:

4

Step-by-step explanation:

1 batch = 2/3

so 6 batches = 2/3 * 6

and 2/3 *6 = 4 !

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A recipe calls for 1 ½ cups of flour, 2/3 cup of white sugar, and 1/3 cup of brown sugar. The recipe makes 6 servings. A) How ma
Goryan [66]
<span>A) How many cups of flour are there per serving? 

</span>1 ½ cups of flour --------<span>6 servings
?     cups of flour ------- 1 serving

      </span>1 ½ 
------------ 
        6 

= 3/2 x 1/6
= 1/4

answer: 1/4 cups of flour per serving

<span>B) how many total cups of sugar(white and brown) are there per serving?
</span>total white and brown: <span>2/3 + 1/3 = 3/3 = 1 cups (combine)

1 cup of sugar (white and brown) </span>--------6 servings
? cups of sugar (white and brown) ------ 1 serving

  1
-----  = 1/6
  6
answer: 1/6 cups of sugar (white and brown) per serving

<span> (c) Suppose you modify the recipe so that it makes 9 servings. How much more flour do you need for the modified recipe than you need for the original recipe?
</span>
3/2  cups of flour --------6 servings
? cups of flour -----------9 servings


  9 * 3/2             
-----------  
      6

= (13 1/2) / 6
= 2 1/4

2 1/4 ( 9 servings) - 1 1/2(6 servings) = 3/4 cups

answer: you need 3/4 more cups of flour

6 0
3 years ago
Read 2 more answers
Write an algebraic expression to represent each verbal expression. 5 times the sum of a number and 1
11111nata11111 [884]

Answer: 5(x+1)

Step-by-step explanation:

Let the number be x

Sum of number and 1 is x+1

5 times the sum is 5(x+1)

3 0
2 years ago
prove that the fast squaring trick for two-digit numbers ending in 5 works. the trick: if you have a 2-digit number that ends in
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The procedure to squaring a two digit number is by multiplying the first number by a integer greater than the number and putting 25 beside it.

Finding the Square of a Value is a simple method. Multiply the specified integer by itself to determine the square number. The square term is always represented as an integer multiplied by two. For example, the square of 5 is 25 multiplied by 5, giving 5×5 = 5² = 25.

What if we want to calculate the square root of a two-digit number . It might be a little challenging. Ordinary multiplication cannot be used to compute the square of two-digit values. This article will show us how to calculate the precise square of such integers.

Simply multiply a single-digit number by itself to find its square. Furthermore, by memorizing the tables from 1 to 10.

We taught about two triangles and how to find the point of any base of a triangle given the other two sides using Pythagoras' theorem.

A right triangle has three sides: the hypotenuse, perpendicular, and base. Pythagoras' theorem states that

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5 0
1 year ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
Step2247 [10]

Answer:

A = 297\pi

Step-by-step explanation:

To solve this problem we need to be familiar with the formula for the surface area of a cone:

A = \pi r(r + \sqrt{h^2+r^2})

We are given the length of a side and the diameter, to calculate the radius divide the diameter in half:

r = \frac{d}{2}\\r = \frac{18}{2}\\r = 9 cm

To calculate the height of the cone, we must use the Pythagorean Theorem:

C^2 = A^2 + B^2

We can treat the side length as the hypotenuse C, the radius as the base A, and solve for height B. Set the expression up like this:

C^2 = A^2 + B^2\\24^2 = 9^2 + B^2\\B^2 = 24^2 - 9^2\\B = \sqrt{24^2 - 9^2}\\B = \sqrt{576 - 81}\\B = \sqrt{495}\\B \approx 22.25

Now we can plug into our original formula:

A = \pi r(r + \sqrt{h^2+r^2})\\A = \pi 9(9+\sqrt{\sqrt{495}^2+9^2}\\A = \pi 9(9+\sqrt{495 + 81}\\A = \pi 9(9+\sqrt{576})\\A = \pi 9(9 + 24)\\A = \pi 9(33)\\A = 297\pi

5 0
2 years ago
Dertermine if each ordered pair is a solution of the equation 5x+2y=2
Ostrovityanka [42]
The answer is C. All you need to do is find the Y values that correspond with the X values. Have a great day 
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