Answer: 5(x +1.5)^2
10(x +1)^2
1/4(x +2)^2
3(x +5/6)^2
Explanation: When your desired form is expanded, it becomes ...
a(x +b)^2 = a(x^2 +2bx +b^2) = ax^2 +2abx +ab^2
This tells you the overall factor (a) is the leading coefficient of the given trinomial. Factoring that out, you can find b as the root of the remaining constant.
a) 5x^2 +15x +11.25 = 5(x^2 +3x +2.25) = 5(x +1.5)^2
b) 10x^2 +20x +10 = 10(x^2 +2x +1) = 10(x +1)^2
c) 1/4x^2 +x +1 = 1/4(x^2 +4x +4) = 1/4(x +2)^2
d) 3x^2 +5x +25/12 = 3(x^2 +5/3x +25/36) = 3(x +5/6)^2
Answer:
Long-day
Explanation:
In the summer, the days are typically longer so it is easier for the longer day plant as it has adapted to that environment.
1) There are three clusters of leaves
2) the longest leaf measures x cm
3) the shortest leaf measures y cm
4) the plant weighs Z grams
5) the widest leaf measures w cm
The answer is D
It contains the base Uracil.
Answer:
The scheme of the tautomers of cytosine, guanine and thymine are found in the attached file
Explanation:
The primary imine-amine tautomerism occurs in heterocyclic compounds where hydrogen may be forming the amino group (primary amine form) or migrate to adjacent nitrogen (imine form), may occur in some nitrogenous bases such as cytosine. Thymine shows double lactam-lactymal tautomy (where hydrogen migrates from the nitrogen atom to the oxygen atom of the heterocycle oxo group (lactam form) and vice versa (lactose form)), and guanine and cytosine can both.
