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3 years ago

What is the relationship between amplitude and volume?

Physics

1 answer:

MrRissso [65]3 years ago

5 0

Answer:

Explanation:

The sound moves in the form of waves. The amplitude is the distance between the highest and the lowest point of a wave. In this way the amplitude indicates the amount of energy that a sound signal contains.

Intensity is the amount of acoustic energy that a sound contains. Intensity is measured in decibels. Volume is a measure of the energy that a signal carries, being a magnitude of intensity.

In this way it is possible to say that the energy of a signal is closely related to its amplitude, but its development over time is also important.

The tone or height is the quality that distinguishes between a high or low sound and a low or high sound.

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Large electric fields in cell membranes cause ions to move through the cell wall. The field strength in a typical membrane is 1.

serg [7]

Explanation:

The given data is as follows.

Electric field (E) = $1 \times 10^{7} N/C$

Charge (e) = $1.6 \times 10^{-19}$ C

Formula to calculate the magnitude of force is as follows.

F = qE

= $1.6 \times 10^{-19} \times 1 \times 10^{7} N/C$

= $1.6 \times 10^{-12} N$

Therefore, we can conclude that magnitude of the force on a calcium ion with charge +e is $1.6 \times 10^{-12} N$ .

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3 years ago

A block of mass m attached to a horizontally mounted spring with spring constant ???? undergoes simple harmonic motion on a fric

Firdavs [7]

Answer:

(E) It would increase by a factor of 2.

Explanation:

Maximum speed (v) is given by:

$v = \omega *A$

Where ω is the angular frequency and A is the amplitude.

The angular frequency of a spring-mass system is given by:

$\omega = \sqrt{\frac{k}{m}}$

Where k is the spring constant and m is the mass of the block attached to the spring.

Therefore, maximum speed can be written as:

$v= A\sqrt{\frac{k}{m}}\\$

Since mass and amplitude are constant values, a relationship between maximum velocity and spring constant can be defined as:

$v =C \sqrt{k}$

There is a linear relationship between maximum velocity and the square root of the spring constant. Therefore if the spring constant is increased by a factor of 4, the velocity is increased by a factor of the square root of 4, which is 2.

The answer is (E) It would increase by a factor of 2.

8 0

3 years ago

What is the maximum height achieved if a 0.600 kg mass is thrown straight upward with an initial speed of 75.0 mÂ·sâ1? ignore th

loris [4]

We can solve the problem by using the law of conservation of energy:

- at the beginning, all mechanical energy of the object is just kinetic energy: $K=\frac{1}{2}mv^2$ , where m is the mass and v is the velocity