Question

3. A -4.00-uC charge lies 20.0cm to the right of a 2.00-uC charge on the x axis. What is the force on the 2.00-uC charge?

Answer 1

Answer:

The force on the 2.00-uC charge is $36 \times 10^{10} \mathrm{N}$

Explanation:

We know that force between two charges is given by Coulomb’s law,

$\mathrm{F}=\mathrm{k} \frac{q 1 q 2}{r * r}$

Where k = Coulomb’s constant =

$9.0 \times 10^{9} \mathrm{Nm}^{2} \mathrm{C}^{-2}$

And q1 and q2 are the charges given to be = -4.00-uC and 2.00-uC charges

And r = distance between the charges = 20 cm = 0.2 m  

Substituting the given values in the formula we get force applied on $2.00\ \mu C$ charge,

F =  $36 \times 10^{10} \mathrm{N}$ attractive force which is the required answer.