All categories

3 years ago

3. A -4.00-uC charge lies 20.0cm to the right of a 2.00-uC charge on the x axis. What is the force on the 2.00-uC charge?

Physics

1 answer:

Sladkaya [172]3 years ago

3 0

Answer:

The force on the 2.00-uC charge is $36 \times 10^{10} \mathrm{N}$

Explanation:

We know that force between two charges is given by Coulomb’s law,

$\mathrm{F}=\mathrm{k} \frac{q 1 q 2}{r * r}$

Where k = Coulomb’s constant =

$9.0 \times 10^{9} \mathrm{Nm}^{2} \mathrm{C}^{-2}$

And q1 and q2 are the charges given to be = -4.00-uC and 2.00-uC charges

And r = distance between the charges = 20 cm = 0.2 m

Substituting the given values in the formula we get force applied on $2.00\ \mu C$ charge,

F = $36 \times 10^{10} \mathrm{N}$ attractive force which is the required answer.

You might be interested in

What is the amount of matter in an object is called?

Sedbober [7]

Answer:

mass

Explanation:

3 0

2 years ago

Read 2 more answers

A small sphere of radius R is arranged to pulsate so that its radius varies in simple harmonic motion between a minimum of R−x a

Colt1911 [192]

Answer:

The intensity of sound wave at the surface of the sphere $I = \frac{ 2\pi^{2}R^{2} f^{2}\sqrt{\rho B}(\triangle R)^{2}}{ d^{2} }$

Explanation:

B = Bulk modulus

Intensity, $I = \frac{P_{max} ^{2} }{2\sqrt{\rho B} }$

The amplitude of oscillation of the sphere is given by:

$P_{max} = BkA\\k = \frac{2\pi }{\lambda} \\$

$A = \triangle R\\$

Substitute v and A into Pmax

$P_{max} = (2\pi f)\sqrt{\rho B} \triangle R\\ P_{max} ^{2} = 4\pi^{2} *f^{2} \rho B (\triangle R)^{2}$

$I = \frac{ 4\pi^{2} f^{2} \rho B (\triangle R)^{2}}{2\sqrt{\rho B} }$

$P_{total} = 4\pi R^{2} I$

$P_{total} =4\pi R^{2} \frac{ 2\pi^{2} f^{2} \rho B (\triangle R)^{2}}{\sqrt{\rho B} }$

The intensity of the sound wave at a distance is given by:

$I = \frac{P_{total} }{4\pi d^{2} }$

$I = 4\pi R^{2} \frac{ 2\pi^{2} f^{2} \rho B (\triangle R)^{2}}{\sqrt{\rho B} } * \frac{1}{4\pi d^{2} } \\I = \frac{ 2\pi^{2}R^{2} f^{2}\sqrt{\rho B}(\triangle R)^{2}}{ d^{2} }$

5 0

3 years ago

The resultant of three vectors is 90.00 cm 34o N of W. If two of these three vectors are 17.89 cm 27o W of S, and 36.00 cm NW, w

Art [367]

Answer:

Magnitude of the third vector: 57.85 cm

The direction of the third vector: 44.76 N of W

Explanation:

8 0

3 years ago

g A simple pendulum (consisting of a point mass suspended by a massless string) on the surface of the earth has a period of 1.00

leonid [27]

Answer:

Explanation:

The formula for time period of a pendulum is given as follows :

T = 2π $\sqrt{\frac{l}{g} }$

l is length of pendulum and g is acceleration due to gravity .

So time period of pendulum is not dependent on the mass of the pendulum . If time period is same and length is also the same then acceleration due to gravity will also be the same . Hence the acceleration due to gravity at distant planet will be same as that on the earth.

5 0

2 years ago

What is energy and types of energy

pishuonlain [190]

Energy- the ability to do work/how things can change and move

Types
Potential Energy
Kinetic Energy
Nuclear Energy
Mechanical Energy
Sound Energy
Heat

8 0

2 years ago

Read 2 more answers