Question

A ball is swung in a horizontal circle at a constant speed. Each circle takes 0.85 seconds to complete and the rope is 0.40 m long. What is the centripetal acceleration?

Answer 1

Answer:

The centripetal acceleration will be "21.785 m/s²".

Explanation:

The given values are:

Time,

t = 0.85 seconds

Length of rope,

r = 0.40 m

Mass of ball,

m = 0.80 kg

As we know,

⇒ $w=\frac{2 \pi}{t}$

On substituting the values, we get

⇒      $=\frac{2\times 3.14}{0.85}$

⇒      $= \frac{6.28}{0.85}$

⇒      $=7.38 \ rad/s^2$

The centripetal acceleration will be:

⇒  $a=r\times w^2$

⇒     $=0.40\times (7.38)^2$

⇒     $=0.40\times 54.46$

⇒     $=21.785 \ m/s^2$