Answer:
the answer to your question is 4 cm long
Explanation:
Answer:
best close estimate distance is 315 miles
Explanation:
given data
speed v1 = 50 miles per hour
speed v2 = 60 miles per hour
time t1 = 4 hr
time t2 = 7 hr
to find out
best estimate for the distance traveled
solution
we know lower end distance
distance = v1 × t1
distance = 50 × 4 = 200 miles
and
upper end distance
distance = v2 × t2
distance = 60 × 7 = 420 miles
so middle value distance is
v = 55 miles per hour and t = 5.5 hours
distance = v × t
distance = 55 × 5.5
distance = 302.5 miles
so best close estimate distance is 315 miles
Answer:
9.98 × 10⁻⁹ C
Explanation:
mass, m = 1.00 × 10⁻¹¹ kg
Velocity, v = 23.0 m/s
Length of plates D₀ = 1.80 cm = 0.018 m
Magnitude of electric field, E = 8.20 × 10⁴ N/C
drop is to be deflected a distance d = 0.290 mm = 0.290 × 10⁻³ m
density of the ink drop = 1000 kg/m^3
Now,
Time =
or
Time =
or
Time = 6.9 × 10⁻⁴ s
Now, force due to the electric field, F = q × E
where, q is the charge
Also, Force = Mass × acceleration
q × E = 1.00 × 10⁻¹¹ × a
or
a =
Now from the Newton's equation of motion
where,
d is the distance
u is the initial speed
a is the acceleration
t is the time
or
or
q = 9.98 × 10⁻⁹ C
The final velocity of the train at the end of the given distance is 7.81 m/s.
The given parameters;
- initial velocity of the train, u = 6.4 m/s
- acceleration of the train, a = 0.1 m/s²
- distance traveled, s = 100 m
The final velocity of the train at the end of the given distance is calculated using the following kinematic equation;
v² = u² + 2as
v² = (6.4)² + (2 x 0.1 x 100)
v² = 60.96
v = √60.96
v = 7.81 m/s
Thus, the final velocity of the train at the end of the given distance is 7.81 m/s.
Learn more here:brainly.com/question/21180604