Answer:
0.75 NC⁻¹
Explanation:
Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,
So, Force (F) = Electric field intensity(E) × Charge (q)
F = E×q ⇒ q = F/E
= 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹
According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted on both charges.
According to cool om's law,
F =G×q1×q2 / r²
F = force exerted of two charges
q1 , q2 = charges
r = distance between two charges
And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge
Answer:
Explanation:
The force of friction between the quails feet and the ground is:
So the coefficient of static is solve
Answer
given,
heat added to the gas,Q = 3300 kcal
initial volume, V₁ = 13.7 m³
final volume, V₂ = 19.7 m³
atmospheric pressure, P = 1.013 x 10⁵ Pa
a) Work done by the gas
W = P Δ V
W = 1.013 x 10⁵ x (19.7 - 13.7)
W = 6.029 x 10⁵ J
b) internal energy of the gas = ?
now,
change in internal energy
Δ U = Q - W
Q = 3300 x 10³ cal
Q = 3300 x 10³ x 4.186 J
Q = 1.38 x 10⁷ J
now,
Δ U = 1.38 x 10⁷ - 6.029 x 10⁵
Δ U = 1.32 x 10⁷ J
