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Sonbull [250]
3 years ago
9

How do you differentiate linear equation from those equatipn which are not linear?​

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

the x

Step-by-step explanation:

Looking at the x in an equation can reveal its shape. A linear graph can look like y=x, y=mx, y=mx+b (m being any number).

When you look at graphs that aren't linear, the x doesn't stand alone in the equation.

Parabolas have a y=x^2 equation. Cubic graphs are y=x^3. They have something attached to the x.

To see all the different kinds of equations and what their graphs look like you can search up "parent functions" and all the basic formulas show up.

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Which equation is not equivalent to the formula r = st?
maksim [4K]
We are given the formula r = st. We evaluate each option to know the correct answer.

A.) S = r/t 
r = st

B.) t = r/s
r = st

C.) s = t/r
r = t/s

<span>D.) r = ts
</span>r = st

Therefore, the correct answer among the choice given is option C. It is not equivalent to the formula.

5 0
3 years ago
Read 2 more answers
Elimination method - -4x = 4y<br> 4x - 8y = 12
nika2105 [10]

Answer: (4,-4)

y=-4, x=4

Step-by-step explanation:

-4x=4y

4x-8y=12

-8y=-4x+12  Now I can substitute -4x for 4y

-8y=4y+12

-2y=y+12

-3y=12

y=-4

-4x=4y

-4x=4(-4)

x=4

6 0
3 years ago
Complete the table for the radioactive iotope. (Round your anwer to 2 decimal place. Iotope : 239 Pu
Marizza181 [45]

If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams

The half life in years = 24100

Consider the quantity of the radio active isotope remaining

y = Ce^{kt}

When t = 1000 the y = 1.2

y = C/2 when t = 1599

Substitute the values in the equation

C/2 = Ce^{24100k}

Cancel the C in both side

1/2 = e^{24100k}

Here we have to apply ln to eliminate the e terms

ln (1/2) = 24100k

k = ln(1/2) / 24100

k = -2.87× 10^-5

To find the initial value we have to substitute the value of k and y in the equation

1.2 = Ce^{1000 ×  -2.87× 10^-5}

C = 1.2 / e^(-0.0287)

C = 2.16 gram

Hence, the initial quantity of the radioactive isotope is 2.16 gram

Learn more about half life here

brainly.com/question/4318844

#SPJ4

7 0
1 year ago
The numbers that satisfy the equation a =5.
madam [21]
<h2>Explanation:</h2>

We use an equation to say that two things are equal. An equation always has an equal sign "=". So an equation tells us that the left side is equal to the right side. In this case, we have the following equation:

a =5

So the only value that makes this equation to be true is 5, because:

5=5

For instance, let's choose another value, say, 8. So substituting:

6 =5 \ \text{So this statement is false because} \ 6\neq 5

5 0
3 years ago
I NEED HELP ASAP<br> HELP
Kisachek [45]
Id say maybe you would have 10 $1 bills and 1 dime and 7 pennies
6 0
2 years ago
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