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Sonbull [250]
3 years ago
9

How do you differentiate linear equation from those equatipn which are not linear?​

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

the x

Step-by-step explanation:

Looking at the x in an equation can reveal its shape. A linear graph can look like y=x, y=mx, y=mx+b (m being any number).

When you look at graphs that aren't linear, the x doesn't stand alone in the equation.

Parabolas have a y=x^2 equation. Cubic graphs are y=x^3. They have something attached to the x.

To see all the different kinds of equations and what their graphs look like you can search up "parent functions" and all the basic formulas show up.

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Help me with the question in the pic please and thank u!
Zepler [3.9K]

Answer:

1.98

Step-by-step explanation:

In this problem, we are:

Given: ∠D = 26°, Hypotenuse (DF) = 4.5

To solve: EF

Now through the given, we are to focus on point D to solve for EF.

We need to find the relationship of point D to DF and EF.

The relationship here is sine.

Reason: \frac{opposite}{hypotenuse}

Through point D, DF is the hypotenuse and EF is the opposite side.

So let's solve this simply through algebra,

sin = \frac{opposite}{hypotenuse}

sin(26°) = \frac{EF}{4.5}

0.44 = \frac{EF}{4.5}

0.44 × 4.5 = EF

1.98 = EF

7 0
4 years ago
Please help me!!!!!!!!!!!!
Aloiza [94]

Answer:

16.03

Step-by-step explanation:

3 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
Can someone help plssss<br> which of the equations below could be the equation of this parabola?
RideAnS [48]

Answer:

C

Step-by-step explanation:

Both of the y= make upward parabolas

It is also going into the positive direction so it is x = \frac{1}{4}y^2

6 0
3 years ago
Read 2 more answers
How do I solve 0.6(-13k-12)
Anton [14]

Answer:

-7.8k - 7.2

Step-by-step explanation:

Distribute 0.6 to the terms in the parentheses:

0.6(-13k - 12)

-7.8k - 7.2

So, the simplified expression is -7.8k - 7.2

4 0
3 years ago
Read 2 more answers
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