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Dmitriy789 [7]
3 years ago
11

The circumference of a clock is 44 inches. Find the

Mathematics
2 answers:
professor190 [17]3 years ago
7 0

Answer:7

Step-by-step explanation:

hope this helped

Brut [27]3 years ago
4 0

Answer:

Click on the picture it explains everything my friend! didnt want to write it out on brianly so yeah. Hope this helps!

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6. Evan has 4 chocolate bars with a total of 48 pieces. How many pieces are in each bar? pieces per bar​
murzikaleks [220]

Answer: 12

Step-by-step explanation: hope this helped

7 0
3 years ago
Read 2 more answers
Let n1equals50​, Upper X 1equals30​, n2equals50​, and Upper X 2equals10. Complete parts​ (a) and​ (b) below. a. At the 0.05 leve
Viefleur [7K]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation  

X_{1}=30 represent the number of people with a characteristic in 1

X_{2}=10 represent the number of people with a characteristic in 2

n_{1}=50 sample of 1 selected  

n_{2}=50 sample of 2 selected  

p_{1}=\frac{30}{50}=0.6 represent the proportion of people with a characteristic in 1

p_{2}=\frac{10}{50}=0.2 represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.  

3 0
3 years ago
Carmelo's height is 2.12 m. Express this measurement in millimeters. Explain your thinking.
Butoxors [25]

Answer:

2120 milimeters

Step-by-step explanation:

to convert meters to milimeters, you need to multiply your value by 1000, so in this case 2.12x 1000= 2120

Hope this helps

5 0
3 years ago
How do you simplify 2+-2<img src="https://tex.z-dn.net/?f=%5Csqrt%7B6%7D" id="TexFormula1" title="\sqrt{6}" alt="\sqrt{6}" align
ehidna [41]
1+(put the little sign)6

that should be the answer, good luck.
7 0
3 years ago
A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando
Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744  

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) \times p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = \frac{\text { number of good coils }}{\text { total number of coils }}

Hence, p(getting 2 good coil for two selection) = \frac{88}{100} \times \frac{88}{100} =\bold{0.7744}

5 0
3 years ago
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