Answer:
Y'=3xy-3x-12
Y'=F(-2,-1)=0
Step-by-step explanation:
The function of the equation at the point (-2,-1)
is where the equation make the function go to zero:
Y'=3xy-3x-12
Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12
F(-2,-1)=[6]-[-6]-12
F(-2,-1)=6+6-12
F(-2,-1)=12-12
F(-2,-1)=0
Solving for y
3xy-3x-12=0
y=4/x+x
Making y=0
So the values make the function go to zero
Answer:
1/(x^3 + 6x^2 + 12x + 8)
Step-by-step explanation:
The first thing we do is rationalize this expression. (2+x)^-3 is written as
1/(2+x)^3
Then from there we can foil out the denominator. It is easiest to foil (2+x)(2+x) first and then multiply that product by (2+x).
(2+x)(2+x) = 4 + 4x + x^2
(4+4x+x^2)(2+x) = 8+8x+2x^2+4x+4x^2+x^3.
Then we combine like terms and put them in order to get:
x^3 + 6x^2 + 12x + 8
And of course we can't forget that this was raised to the negative third power, so our answer is 1/(x^3 + 6x^2 + 12x + 8)
Answer:
y = 20°
x = 35°
Explanation:
Equation's:
1) 2y + x + 105° = 180°
2) 3x + x + 2y = 180°
Make y subject in equation 2
3x + x + 2y = 180
4x + 2y = 180
2y = 180 - 4x
y = 90 - 2x
Insert this into equation 1
2(90 - 2x) + x + 105° = 180°
180 - 4x + x + 105 = 180
-3x = -105
x = 35°
Find value of y
y = 90 - 2x
y = 90 - 2(35)
y = 20°
